Answer:
1) for -1 as x, k(x) would be -8
2) for -3 as x, k(x) would be -18
3) for 0 as x, k(x) would be -3
4) for 1 as x, k(x) would be 2
Answer:
Step-by-step explanation:
hello :
16t²+120 = y
16t² = y -120 so : t² = (y-120)/16
if : y-120 ≥ 0 t = ±√((y-120)/16)
Answer:
845.6306
Step-by-step explanation:
Firstly this is annuity based
Let, investment at beginning of year = <em>x</em>
Then value at year 1 end = x + (8.2%
x)
Value at end of year 2 = (x + 0.082x) + (8.2%
(x + 0.082x))
Now this value = $990
Therefore,
990 = (x + 0.082x) + ((x + 0.082x)
8.2%)
990 = x + 0.082x + 0.082x + 0.006724x = 1.170724x
x = 990/1.170724 = 845.6306
Y = -7x + 2
y = 9x - 14
-7x + 2 = 9x - 14
14 + 2 = 9x + 7x
16 = 16x
1 = x
y = -7x + 2
y = -7(1) + 2
y = -7 + 2
y = -5
solution is : (1,-5) <==