For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
Answer:
14 square units
Step-by-step explanation:
If you graph the points your triangle's height will be 4, and base would be 7.
<em>A = 1/2bh 4</em> x 7 = 28, 28 x 1/2 = 14.
Hope this helps :D
What's the given quantity?
