A and b are legs
a^2+b^2=c^2
lets say
a>b
so
a=13+3b
c=14+3b
a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative
b-9=0
b=9
shorter leg is 9
a=13+3b
a=13+3(9)
a=13+27
a=40
c=14+3b
c=14+27
c=41
side legnths are
9in, 40in, 41in
Answer:
thank you
Step-by-step explanation:
can I get brainiest please
Answer:
Answer below
Step-by-step explanation:
Yo uneed to find the Area/volume
The area of the rectangle is 2×(5cm×1cm)+2(3cm×1cm)+2(5cm×3cm)=10cm+6cm+30cm=36cm^2
Volume=5cm×3cm×1cm=15cm^3
Ratio: 36cm^2/15cm^3=12cm^2/5cm^3
<em>2 solutions</em>
<em>X= 16</em>
<em>X=49</em>
Step-by-step explanation:
<em>original equation</em>
<em>x-11√x+28 = 0</em>
<em> Isolate</em>
<em> -11√x = -x-28+0</em>
<em> Tidy up</em>
<em> 11√x = x+28</em>
<em> Raise both sides to the second power</em>
<em> (11√x)2 = (x+28)2</em>
<em>After squaring</em>
<em> 121x = x2+56x+784</em>
<em> Plug in 49 for x </em>
<em> 11√(49) = (49)+28</em>
<em>Simplify</em>
<em> 11√49 = 77</em>
<em> Solution checks !!</em>
<em> Solution is:</em>
x = 49
<em>Plug in 16 for x </em>
<em> 11√(16) = (16)+28</em>
<em>Simplify</em>
<em> 11√16 = 44</em>
<em> Solution checks !!</em>
<em> Solution is:</em>
x = 16
Answer:
x= 500 y= 1500
Step-by-step explanation:
Isolate x or y in the first equation
Isolating for x would be x= -y+2000
Substitute X=-y+2000 into equation 10x+20y=35000
10(-y+2000)+20y=35000
Exapnd the equation above and you should get y=1500
Same steps for finding x by isloating for y
