Sin³(x)cos⁴(x) = sin(x)[cos⁴(x) - cos⁶(x)]
sin(x) sin(x)
sin²(x)cos⁴(x) = cos⁴(x) - cos⁶(x)
sin²(x)cos⁴(x) = cos⁴(x)[1] - cos⁴(x)[cos²(x)]
sin²(x)cos⁴(x) = cos⁴(x)[1 - cos²(x)}
cos⁴(x) cos⁴(x)
sin²(x) = 1 - cos²(x)
+ cos²(x) + cos²(x)
1 = 1
My question to your answer is 1
T- Triangle sum and Third angles theorems
R- Right Triangle
I- Isosceles Triangle
A- Acute Angles
N- n-fold rotation symmetry for "E" triangles
G- Geometry
L- Legs of a triangle
E- Equilateral and Equiangular Triangles
Answer:
A. Algebraic, common difference = −10
Step-by-step explanation:
The difference between the first two terms is -10, as it is between the next two terms. The ratio of the first two terms is -1; of the next pair: -15/-5 = 3. There is a common difference, but not a common ratio.
The sequence is algebraic with a common difference of -10.
Hello. D= 2×r D=2×2,8 D=5,6cm. Circumference=
× D ;
C= 3,14×5,6 C=17,584cm. I hope to have helped you.
