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2 years ago

What point of concurrency in a right triangle is also the midpoint of the hypotenuse?

Mathematics

2 answers:

tekilochka [14]2 years ago

8 0

The correct answer is d, i got it right

Arada [10]2 years ago

3 0

The correct answer is D

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Please I need your help on this.

just olya [345]

Answer:

the answer is 7 7/8

Step-by-step explanation:

1. you will need to change the fractions into an improper fraction.

2. you need to then multiply the numerator and denominator to get a 63/8

3. change 63/8 into a mixed fraction leaving you with 7 7/8

8 0

3 years ago

(-2, 11) & (5,6) What is the slope of the equation between these two points?

ololo11 [35]

Answer:

$m =\dfrac{-5}{7}$

Step-by-step explanation:

Given :-

Two points (-2,11) and (5,6) .

And we need to find out the slope of the equation between the two points. The slope of the line passing through two points , is given by ,

$\implies Slope (m) =\dfrac{ y_2-y_1}{x_2-x_1}$

Here the two points are (-2,11) and (5,6) .So put on the respective values ,

$\implies Slope (m) =\dfrac{ 11 - 6}{-2-5}\\\\\implies Slope = \dfrac{5}{-7} \\\\\implies Slope = \dfrac{-5}{7}$

Hence the slope of the line is -5/7 .

8 0

2 years ago

In the equation x+44=136, what is x?

ad-work [718]

The answer is 92. subtract 44 from 136 and you get x = 92

6 0

3 years ago

Find the measure of each marked angle. (9x-27) (4x)

valkas [14]

Answer:

(9×-27)

= (243×4)

= 972

5 0

2 years ago

List the ordered pairs in the equivalence relations produced by these partitions of {a, b, c, d, e, f, g}: a) {a,b},{c,d},{e,f,g

finlep [7]

Answer:

a) {a,b} , {c,d} , {e,f,g},{a , b } = {(a,a) (b,b) (a,b) (b,a)},{c , d } = {(c,c) (d,d) (c,d) (d , c) } ,{e,f,g} = {(e,e) (e,f) (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f)(g,g)}

b) { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)

c) {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

Step-by-step explanation:

a) {a,b} , {c,d} , {e,f,g}

{a , b } = {(a,a) (b,b) (a,b) (b,a)}

{c , d } = {(c,c) (d,d) (c,d) (d , c) }

{e,f,g} = {(e,e) (e,f) (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f) (g,g)}

b) {a} ,{b},{c,d} ,{e,f},{g}

{ (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)}

c) {a,b,c,d},{e,f,g}

{(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

4 0

3 years ago