Question Write an equation of the line passing through the point A(0, 3) that is perpendicular to the line y = −1/2x−6

Mathematics

1 answer:

White raven [17]2 years ago

7 0

Answer:

The equation would be y=2x+3 I am pretty sure

Step-by-step explanation:

This is because you take the slope which is 2 from the line y=-1/2x-6. To find the slope perpendicular to the line, you need to find the exact opposite of the slope: -1/2, and in this case, it would be 2.

(Ex: if it was -3/4, you would need to use a slope of 4/3 since it is the opposite)

Then you take that slope (2) and the point (0, 3) and put it into "y-y1=m(x-x1)"

y-y1=m(x-x1)

y-3=2(x-0)

-distribute the 2-

y-3=2x-0

-add 3 on both sides-

so equation would be y=2x+3

Not sure if this is all correct, but I hope it helps! :)

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Crash testing is a highly expensive procedure to evaluate the ability of an automobile to withstand a serious accident. A simple

Veseljchak [2.6K]

Answer:

The 95% confidence interval is (-0.2451, 06912)

Step-by-step explanation:

From the question, we have;

The number of small cars in the sample of small cars, n₁ = 12

The number of small cars that were totaled, x = 8

The number of large cars in the sample of small cars, n₂ = 15

The number of large cars that were totaled, y = 5

Therefore, the proportion of small cars that were totaled, pX = x/n₁

∴ pX = 8/12 = 2/3

The proportion of large cars that were totaled, pY = y/n₁

∴ pY = 5/15 = 1/3

The 95% confidence interval for the difference pX - pY is given as follows;

$pX-pY\pm z^{*}\sqrt{\dfrac{pX\left (1-pX \right )}{n_{1}}+\dfrac{pY\left (1-pY \right )}{n_{2}}}$

$\dfrac{2}{3} -\dfrac{1}{3} \pm 1.96 \times \sqrt{\dfrac{\dfrac{2}{3} \times \left (1-\dfrac{2}{3} \right )}{12}+\dfrac{\dfrac{1}{3} \times \left (1-\dfrac{1}{3} \right )}{15}}$