Answer:
I think it is the second one
Step-by-step explanation:
Answer:
Domain: -4 < x < 4
Zeros: (-2, 0), (0, 0) and (2, 0)
The function is positive if: 0 < x < 2
The function is negative if: -4 < x < 0 and 2 < x < 4
Step-by-step explanation:
Domain of the function are those x values where the function is defined, For this case, -4 < x < 4
Zeros of a function are those x values where y = 0, that is, the graph intersect x-axis. For this case, the points are: (-2, 0), (0, 0) and (2, 0)
The function is positive if the graph o the function is above x-axis. For this case, the function is positive at the interval (0, 2)
The function is negative if the graph o the function is below x-axis. For this case, the function is negative at the intervals (-4, 0) and (2, 4)
Answer: Angles A and C are vertical angles.
Step-by-step explanation:
David's pumpkin cost $8.22
His sister's pumpkin cost $4.98
They paid $13.20
Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).