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lbvjy [14]
3 years ago
8

A steel safe with mass 2200 kg falls onto concrete. Just

Mathematics
1 answer:
Virty [35]3 years ago
5 0

The kinetic energy of the safe increases the force exerted by the concrete

to several times the weight of the safe.

  • The magnitude of the force exerted on the safe by the concrete on the is approximately \underline{29.\overline 3 \, \mathrm{MN}}
  • The concrete exerts a <u>force</u> that is approximately <u>1,359.16 times the weight of the safe</u>.

Reasons:

First part

The mass of the steel safe, m = 2,200 kg

Velocity of the safe just before it hits the concrete, v = 40 m/s

The amount by which the safe was compressed, d = 0.06 m

The kinetic energy, K.E., of the safe just before it hits the round is therefore;

\displaystyle K.E. = \mathbf{\frac{1}{2} \cdot m \cdot v^2}

\displaystyle K.E._{safe} = \frac{1}{2} \times 2,200 \times 40^2 = 1,760,000 \ Joules

Work done by concrete, W = Force, F × Distance, d

  • \displaystyle Force, \, F = \mathbf{\frac{Work, \, W}{Distance, \, d}}

By the law of conservation of energy, we have;

The work done by the concrete, W = The kinetic energy, K.E. given by the safe

W = K.E. = 1,760,000 J

The effect of the work = The change in the height of the safe

Therefore;

The distance, <em>d</em>, over which the force of the concrete is exerted = The change in the height of the safe = 0.06 m

d = 0.06 m

Therefore;

\displaystyle The \ force \ of \ the \ concrete, \, F = \frac{1,760,000\, J}{0.06 \, m} = 29,333,333. \overline 3 \, N = 29.\overline 3 \ MN

  • The force of the concrete on the safe = \underline{29.\overline 3 \ MN}

Second part:

The gravitational force of the Earth on the safe, W = The weight of the safe

W = Mass, m × Acceleration due to gravity, g

W = 2,200 kg × 9.81 m/s² ≈ 21,582 N

The ratio of the force exerted by the concrete to the weight of the safe is found as follows;

\displaystyle Ratio \ of \ forces = \frac{29.\overline 3 \times 10^6 \, N}{21,582 \, N} = \frac{4,000,000}{2,943} \approx \mathbf{1359.16}

  • The <u>force</u> exerted by the concrete is approximately <u>1,359.16 times the weight of the safe</u>.

Learn more here:

brainly.com/question/21060171

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