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Vladimir [108]
2 years ago
15

49583747 x 374747 corrext awnser gets brainliest 5 star and a heart​

Mathematics
1 answer:
Nonamiya [84]2 years ago
5 0

Answer:

=18,581,360,437,009

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Solve the expressions on the left when x=5<br>3x-10<br>x^2-15<br>5x-21<br>x+10-8​
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Answer:

5

10

4

7

Step-by-step explanation:

Apply the value of x into the expressions:

3(5) - 10 = 15 - 10

           = 5

5² - 15 = 25 - 15

          = 10

5(5) - 21 = 25 - 21

             = 4

5 + 10 - 8 = 15 - 8

               = 7

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F(x)=bx^2+32 For the function f defined above, b is a constant and f(2)=40. What is the value of f(-2)?
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Answer:

f(-2) = 0

Step-by-step explanation:

Given that:

f(x) = bx^2 + 32

f(2) = b(2)^2 + 32

f(2) = 4b + 32

f(2) = 4b = -32

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f(2) = b = -8

Thus;

f(-2) = -8(-2)^2 + 32

f(-2) = -8(4) + 32

f(-2) = -32 + 32

f(-2) = 0

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