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2 years ago

Please help need to turn in

Chemistry

2 answers:

ohaa [14]2 years ago

8 0

Answer:

2. d

3. i

4. e

5. j

6. g

7. a

8. f

9. b

Explanation:

do a few searches when you have time to deepen understanding!

nignag [31]2 years ago

7 0

5. j
6. g
4. e
9. b
2. d
7. a
10. h
1. c
3. f

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Determine whether the material is a mineral or a non-mineral based on the description

almond37 [142]

Answer:

Calcium is homogeneous Three percent of Earth's crust is made of calcium Mineral
Glycerin is a viscous liquid at room temperature. Non-mineral
Emerald is hard and does not decay. Its chemical formula is Be3Al2(SIO3)6 Mineral
Chlorophyll is produced in plants during photosynthesis Non-mineral

Explanation:

Minerals are generally solid and inorganic substances, with defined crystalline structures, that exist in the earth's crust, formed by one or more chemical elements.

Calcium is the fifth element in abundance in the earth's crust, it is found forming mineral compounds such as calcite and dolomite or rocks such as marble, limestone and dolomite.

Glycerin is a colorless, slimy and sweet-tasting substance that is obtained from animal and vegetable fats and oils. According to its characteristics, it does not have a solid structure, which is why it is considered a non-mineral.

Emerald is a cyclic silicate of beryllium and aluminum whose chemical formula is Be3Al2(SiO3)6, it has a well-defined crystalline structure.

Chlorophyll is a green pigment that is present in the leaves and stems of many vegetables and is responsible for the photosynthesis process; does not have a crystalline structure defined by what is considered a non-mineral.

3 0

3 years ago

Read 2 more answers

What mass of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution?

inna [77]

Answer:

459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution

Explanation:

Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

$Molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$

In this case:

Molarity: 1.56 M= 1.56 $\frac{moles}{liter}$
Number of moles of calcium chlorine= ?
Volume= 2.657 liters

Replacing:

$1.56 M=\frac{Number of moles of calcium chlorine}{2.657 liters}$

Solving:

Number of moles of calcium chlorine= 1.56 M* 2.657 liters

Number of moles of calcium chlorine= 4.14 moles

In other side, you know:

Ca: 40 g/mole
Cl: 35.45 g/mole

Then the molar mass of the calcium chloride CaCl₂ is:

CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole

Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?

$mass=\frac{4.14 moles*110.9g}{1 mole}$

mass= 459.126 g

459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution

3 0

3 years ago

Can anyone check my chemistry answers?

frutty [35]

I check all of them. most of them correct but one

in question 6, the answer is the third choice. remember to find the neutrons, you take the atomic mass minus the atomic number. 38 - 18= 20

4 0

4 years ago

A 112 gram sample of an unknown metal was heated from 0.0C to 20.0C. The sample absorbed 1004 J of energy. What was the specific

worty [1.4K]

Answer:

The specific heat of the sample unknown metal is approximately 0.45 J/g °C.

General Formulas and Concepts:
Thermodynamics

Specific Heat Formula: $\displaystyle q = mc \triangle T$

m is mass (g)
c is specific heat capacity (J/g °C)
ΔT is the change in temperature

Explanation:

Step 1: Define

Identify variables.

m = 112 g

ΔT = 20.0 °C

q = 1004 J

Step 2: Solve for c

Substitute in variables [Specific Heat Formula]: $\displaystyle 1004 \ \text{J} = (112 \ \text{g})(c)(20.0 \ ^{\circ} \text{C})$
Simplify: $\displaystyle 1004 \ \text{J} = (2240 \ \text{g} \ ^\circ \text{C})c$
Isolate c: $\displaystyle c = 0.448214 \ \text{J} / \text{g} \ ^\circ \text{C}$
Round [Sig Figs]: $\displaystyle c \approx 0.45 \ \text{J} / \text{g} \ ^\circ \text{C}$