Answer:
See below
Explanation:
The common formula of the same alkene series is CnH2n, where n is the quantity of atoms of carbon. Owing to the hydrocarbons of alkenes with at least one double carbon relation, the alkene-like sequence starts with ethen C2H4.
<em><u>Hope this helps.</u></em>
Mole fraction is expressed as the number of moles of solute over the total number of moles of solute and the number of moles of solvent. When expressed in molal, this is equal to number of moles of solute per liter solvent. If the mole fraction is 1.00, this means, all that is in the solution is solute. Hence the molal equivalent is 1.00 too
Answer:
C₁₃H₁₈O₂
Explanation:
Empirical formula is the simplest ratio in moles of the elements presents in the compound. Assuming a basis of 100g, we need to convert the mass of each element to moles and, find the ratio of each of these:
<em>Moles C:</em>
75.69g * (1mol / 12.01g) = 6.3 moles of C
<em>Moles H:</em>
8.80g * (1mol / 1.01g) = 8.7 moles of H
<em>Moles O:</em>
15.51g * (1mol / 16g) = 0.97 moles of O
The ratio dividing in the moles of O -Because is the element with the lower amount of moles-:
C = 6.3mol / 0.97mol = 6.5
H = 8.7mol / 0.97mol = 9
O = 0.97mol / 0.97mol = 1
As the ratio must be in whole-numbers, multiplying in 2:
C = 13;
H = 18
O = 2
And empirical formula is:
<h3>C₁₃H₁₈O₂</h3>
5604000gallon =21239160 liters
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