How to know if java is installed on a server.

Given parameters b and h which stand for the base and the height of an isosceles triangle (i.e., a triangle that has two equal s

schepotkina [342]

Answer:

The area of the triangle is calculated as thus:

$Area = 0.5 * b * h$

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

$s = \sqrt{b^2 + h^2}$

The perimeter of the triangle is then calculated as thus;

$Perimeter = s + s + b$

$Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b$

$Perimeter = 2\sqrt{b^2 + h^2} + b$

For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

$Volume = \frac{1}{3} \pi * r^2 * h$

Where $r = \frac{1}{2} * diameter$

So, $r = \frac{1}{2}b$

So, $Volume = \frac{1}{3} \pi * (\frac{b}{2})^2 * h$

Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

//Calculate Perimeter

double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;

//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

return 0;

}

3 0

2 years ago

Write a program that defines an interface having the following methods: addition, subtraction, multiplication, and division. Cre

Tatiana [17]

Hello, you haven't provided the programing language in which you need the code, I'll explain how to do it using Python, and you can follow the same logic to make a program in the programing language that you need.

Answer:

1. # -*- coding: utf-8 -*-

2. #Python

3. class Calculator:

4. def add(self):

5. print(a + b)

6. def sub(self):

7. print(a - b)

8. def mul(self):

9. print(a * b)

10. def div(self):

11. print(a / b)

12.

13. obj = Calculator()

14. choice = 1

15. while choice != 0:

16. a = int(input("\nEnter first number: "))

17. b = int(input("Enter first number: "))

18.

19. print("\n0. EXIT")

20. print("1. DIVISION")

21. print("2. ADDITION")

22. print("3. SUBTRACTION")

23. print("4. MULTIPLICATION")

24.

25. choice = int(input("\nEnter your choice: "))

26. if choice == 1:

27. obj.div()

28. elif choice == 2:

29. obj.add()

30. elif choice == 3:

31. obj.sub()

32. elif choice == 4:

33. obj.mul()

34. else:

35. break

Explanation:

From lines 1 to 12 we define the object with four methods, addition, subtraction, multiplication, and division. Each method contains the operation between two variables inside a print function
On line 13 we instantiate our class
On line 14 we declare the variable choice that is going to store the operation that the user wants to perform
On line 15 we declare a while loop, this is going to keep running the program until the user wants to exit
From line 16 to 18 we ask the user to enter two numbers
From line 19 to 24 we print the possible operation, assigning a number for each operation, this indicates to the user what number to press for what operation
On line 25 we ask the user for the operation
From lines 26 to 35 we check the user input an accordingly we call the corresponding method to performs the operation

7 0

3 years ago

In which encryption strategy is the plaintext encrypted one character at a time and each encrypted character depends on that sin

Natasha_Volkova [10]

Answer:

Caesar cipher

Explanation:

In formation technology, cryptography or cryptology is a process of coding or encrypting information, using algorithms and input values in a network, where there is a present of a third party called adversaries or attackers.

There are different types of cryptography, namely, symmetric, assymmetric and hash cryptography.

Ciphers are algorithms used in cryptography to encode (encrypt) or decode (decrypt) information. An example of cipher is the Ceasar's cipher.

Ceasar cipher is a simple type of substitution cipher that encrpts plain text one character at a time and each coded character depends on the single character and a fixed distance value.

4 0

3 years ago

Write a static method that implements a recursive formula for factorials. Place this method in a test program that allows the us

matrenka [14]

Answer:

Written in Java

import java.util.*;

public class Main {

public static int fact(int n) {

if (n == 1)

return n;

else

return n * fact(n - 1);

}

public static void main(String[] args) {

int num;

Scanner input = new Scanner(System.in);

char tryagain = 'y';

while(tryagain == 'y'){

System.out.print("Number: ");

num = input.nextInt();

System.out.println(num+"! = "+ fact(num));

System.out.print("Try another input? y/n : ");

tryagain = input.next().charAt(0);

}

Explanation:

The static method is defines here

public static int fact(int n) {

This checks if n is 1. If yes, it returns 1

if (n == 1)

return n;

If otherwise, it returns the factorial of n, recursively

else

return n * fact(n - 1);

}

The main method starts here. Where the user can continue executing different values of n. The program keep prompting user to try again for another number until user signals for stoppage

public static void main(String[] args) {

This declares num as integer

int num;

Scanner input = new Scanner(System.in);

This initializes tryagain as y

char tryagain = 'y';

This checks if user wants to check the factorial of a number

while(tryagain == 'y'){

This prompts user for input

System.out.print("Number: ");

This gets user input

num = input.nextInt();

This passes user input to the function and also prints the result

System.out.println(num+"! = "+ fact(num));

This prompts user to try again for another value

System.out.print("Try another input? y/n : ");

This gets user response

tryagain = input.next().charAt(0);

}

Download txt

4 0

2 years ago

The 'client area' of a window is the area used to display the contents of the window (thus a title bar or border would lie outsi

Stolb23 [73]

Answer:

The Java code is given below

Explanation:

Window.java: 

public class Window {

private int width, height;

public Window(int width, int height) {

this.width = width;

this.height = height;

}

public int getHeight() {

return height;

}

public void setHeight(int height) {

this.height = height;

}

public int getWidth() {

return width;

}

public void setWidth(int width) {

this.width = width;

}

@Override

public String toString() {

return "Window [width=" + width + ", height=" + height + "]";

}

TitledWindow.java:

public class TitledWindow extends Window {

private int barHeight;

public TitledWindow(int width, int height, int barHeight) {

super(width, height);

this.barHeight = barHeight;

}

public int getClientAreaHeight() {

return barHeight + super.getHeight();

}

@Override

public String toString() {

return "TitledWindow [width=" + super.getWidth() + ", height=" + super.getHeight() + ", barHeight=" + barHeight + "]";

}

TestWindows.java: 

public class TestWindows {

public static void main(String args[]) {

Window w = new Window(450, 200);

System.out.println("Window: " + w);

TitledWindow titledWindow = new TitledWindow(450, 200, 30);

System.out.println("titaledWindow: " + titledWindow);

System.out.println("titledWindow.height: " + titledWindow.getClientAreaHeight());

}

6 0

3 years ago