The answer to the maxillary partial denture and the mandibular partial denture respectively are; Palatal connector and Lingual Connector
<h3>Understanding Dental Health</h3>
Maxillary partial denture is a dental prosthetic that allows for the placement of a series of artificial teeth in an area in the upper jaws where healthy teeth used to exist.
Meanwhile, Mandibular Partial Denture is a dental prosthetic that allows for the placement of a series of artificial teeth in an area in the lower jaws where healthy teeth used to exist.
Now, a maxillary partial denture has a palatal connector while a mandibular partial denture has a lingual connector.
Read more about dental health at; brainly.com/question/24345244
Answer:
a = 6, b = 0
Explanation:
The loop ran 3 times before b == 0. "while ((b != 0)" is essentially saying: 'While b is not equal to 0, do what's in my loop'. Same general thing with "&& ((a / b) >= 0)". The "&&" is specifying that there should be another loop condition, while the rest states: 'as long as a ÷ b is greater than 0, do what's in my loop'. If both of these conditions are met, the loop will run, It will continue this until the conditions are not met. Hope that helped! :)
Home is the answer. Hope this helps. :)
Answer:
public class Digits
{
public static boolean allDigitsOdd(int num)
{
boolean flag=true;
int rem;
while(num>0)
{
rem=num%10;
num=num/10;
if(rem%2==0) // if a even digit found immediately breaks out of loop
{
flag=false;
break;
}
}
return flag; //returns result
}
public static void main(String args[])
{
System.out.println(allDigitsOdd(1375)); //returns true as all are odd digits
}
}
OUTPUT :
true
Explanation:
Above program has 2 static methods inside a class Digits. Logic behind above function is that a number is divided by 10 until it is less than 0. Each time its remainder by 0 is checked if even immediately breaks out of the loop.
