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s344n2d4d5 [400]
2 years ago
10

I WILL REPORT FOR ANY LINKS

Mathematics
1 answer:
blsea [12.9K]2 years ago
6 0
The wording “No more than” tells us that the total can be up to 35, but not more. So we can use the less than or equal to sign, ≤


So what she spends, must be less than or equal to 35:

6.25s+14.95 ≤ 35
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Franklin uses the distributive property to write an expression equivalent to 18 + 36. Which of the following best represents Fra
allsm [11]
18+36=54
i tried to do all of these and none of them add up to 54
6 0
3 years ago
Read 2 more answers
Find the volume v of the described solid s. the base of s is an elliptical region with boundary curve 4x2 + 9y2 = 36. cross-sect
Tasya [4]
4x^2+9y^2=36\iff\dfrac{x^2}9+\dfrac{y^2}4=1

defines an ellipse centered at (0,0) with semi-major axis length 3 and semi-minor axis length 2. The semi-major axis lies on the x-axis. So if cross sections are taken perpendicular to the x-axis, any such triangular section will have a base that is determined by the vertical distance between the lower and upper halves of the ellipse. That is, any cross section taken at x=x_0 will have a base of length

\dfrac{x^2}9+\dfrac{y^2}4=1\implies y=\pm\dfrac23\sqrt{9-x^2}
\implies \text{base}=\dfrac23\sqrt{9-{x_0}^2}-\left(-\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac43\sqrt{9-{x_0}^2}

I've attached a graphic of what a sample section would look like.

Any such isosceles triangle will have a hypotenuse that occurs in a \sqrt2:1 ratio with either of the remaining legs. So if the hypotenuse is \dfrac43\sqrt{9-{x_0}^2}, then either leg will have length \dfrac4{3\sqrt2}\sqrt{9-{x_0}^2}.

Now the legs form a similar triangle with the height of the triangle, where the legs of the larger triangle section are the hypotenuses and the height is one of the legs. This means the height of the triangular section is \dfrac4{3(\sqrt2)^2}\sqrt{9-{x_0}^2}=\dfrac23\sqrt{9-{x_0}^2}.

Finally, x_0 can be chosen from any value in -3\le x_0\le3. We're now ready to set up the integral to find the volume of the solid. The volume is the sum of the infinitely many triangular sections' areas, which are

\dfrac12\left(\dfrac43\sqrt{9-{x_0}^2}\right)\left(\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac49(9-{x_0}^2)

and so the volume would be

\displaystyle\int_{x=-3}^{x=3}\frac49(9-x^2)\,\mathrm dx
=\left(4x-\dfrac4{27}x^3\right)\bigg|_{x=-3}^{x=3}
=16

6 0
3 years ago
Please help me dew in 5 minets
Andreyy89

Answer:

false

Step-by-step explanation:

it's false because -5 is less than 2 and a good way to remember the sign is that the bigger number gets eaten

6 0
3 years ago
Read 2 more answers
What time is shown on the clock?
Scorpion4ik [409]

Answer:

it is 11:00 o'clock

havea great dayy

3 0
3 years ago
Read 2 more answers
How do you solve this problem for x?<br> 2^x = 5
Tema [17]
       2^x = 5
-> log2^x = log5
-> xlog2 = log5
-> x = log5/log2
-> x = 2.322

The approximate answer is 2.322
7 0
3 years ago
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