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Ymorist [56]
3 years ago
13

What time is shown on the clock?

Mathematics
2 answers:
yan [13]3 years ago
5 0

Answer:

11:00 o'clock

have a great day God bless you

Scorpion4ik [409]3 years ago
3 0

Answer:

it is 11:00 o'clock

havea great dayy

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Sunny_sXe [5.5K]
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3 years ago
Nedddddddddd helpppppppppppppp
Law Incorporation [45]

Answer:

m= -3

Step-by-step explanation:

using slope formula (Y2-Y1)/(X2-X1)

(9-3)/(8-10)

6/-2

m= -3

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3 years ago
Bus A travelled 20 kilometers and Bus B travelled 200,000 meters. Who travelled the farthest
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3 years ago
Sentence to match the expression 3 + (4 x 12)
aleksklad [387]

Answer:

four multiplied by twelve plus three

Step-by-step explanation:

using order of operations, you solve the multiplication before the addition, so put that first.

3 0
3 years ago
He number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the
denis-greek [22]

The function that represents the number of E.coli bacteria cells per 100 mL of water as t years elapses, and is missing in the question, is:

A(t)=136(1.123)^{4t}

Answer:

   Option A. 59%

Explanation:

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function::

  • A(t)=136(1.123)^{4t}

  • rate=(1.123)^{4t}=(1.123)^4=1.590

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

You can calculate it also using two consecutive values for t. For instance, use t =1 and t = 1

t=1\\\\ A(1)=136(1.123)^4\\\\\\t=2\\ \\ \\A(2)=136(1.123)^8\\ \\ \\A(2)/A(1)=1.123^8/1.1123^4=1.123^4=1.590

6 0
3 years ago
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