(f-g)(x) = f(x) - g(x)
= (x^3 -2x+6) - (2x^3+3x^2-4x+2)
= x^3 -2x +6 -2x^3 -3x^2 +4x -2 . . . . distribute the negative sign
= (1-2)x^3 -3x^2 +(-2+4)x +(6-2) . . . . . combine like terms
(f-g)(x) = -x^3 -3x^2 +2x +4
Answer:
6.04 inches
Step-by-step explanation:
Given: The actual height of the monument = 604 feet
The scale used by Corbins is 1 inch = 100 feet
It implies in Corbins model 1 feet
Therefore, The height of the Corbins model in inches=
Hence, the height of the Corbins model in inches= 6.04 inches
She needs 10 more plates to get 30
For every 3 packages, she uses 1/2 a roll of wrapping paper
if she uses 2 1/2 rolls.....
(2 1/2) / (1/2) ....* 3
(5/2) / (1/2).....* 3
(5/2 * 2) * 3
5 * 3 =
15 packages <===
Since angles 3 and 4 are supplementary, they add up to 180 degrees.
Angle 3 is 88 degrees.
To get the measure of the last angle, let's subtract 88 from 180.
180 - 88 = 92
Thus, Angle 4 has a measure of 92 degrees.
Have an awesome day! :)