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2 years ago

A rectangle has a width of 5 inches and a length of 9 inches. What will be the new dimensions of the rectangle after it is

Mathematics

2 answers:

kondor19780726 [428]2 years ago

8 0

Answer:

the third one

Step-by-step explanation:

iiiieeeeew edgeuinty

Kamila [148]2 years ago

3 0

Answer:

15 inch. By 27 inch.

Step-by-step explanation:

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Solve 2.02W = -3.636

ValentinkaMS [17]

Answer: W=-1.8

Step-by-step explanation:

Divide both sides by 2.02 and you are left with W=-1.8.

Hope this helps!

7 0

2 years ago

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olganol [36]

Answer:

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Alco

8 0

2 years ago

The glee club has a set of 48 classical cds and a set of 42 show tune cds. each set can be divided equally among the club member

Hoochie [10]

We have to find the GCF (Greatest Common Factor) of 48 and 42 here...

Factors of 48:
1,2,3,4,6,8,12,16,24,48

Factors of 42:
1,2,3,6,7,14,21,42

The largest common factor of these two numbers is 6.

So, there can be a maximum of 6 members in the club..

Hope this helped!

6 0

3 years ago

Read 2 more answers

A wire 15 cm long is cut into two pieces. The longer piece is 3.cmidonger than the shorter piece.Find the length of the shorter

Andre45 [30]

A piece of wire is cut into two pieces. That means each part would be assigned an unknown variable. Let one part be x and the other part be y.

That means,

$x+y=15\operatorname{cm}$

If the longer part is x, and the longer part is 3cm longer than the shorter part, then we would have the following;

$\begin{gathered} x+y=15 \\ x=y+3 \\ \text{This is because x is 3cm longer,} \\ So\text{ the length of x would be y+3} \end{gathered}$

We can now refine the equation as follow;

$\begin{gathered} \text{Where;} \\ x=y+3 \\ x+y=15 \\ y+3+y=15 \\ 2y+3=15 \\ \text{Subtract 3 from both sides;} \\ 2y+3-3=15-3 \\ 2y=12 \\ \text{Divide both sides by 2;} \\ \frac{2y}{2}=\frac{12}{2} \\ y=6 \\ \text{When;} \\ x+y=15 \\ x+6=15 \\ \text{Subtract 6 from both sides;} \\ x+6-6=15-6 \\ x=9 \end{gathered}$

ANSWER:

The length of the shorter piece of wire is 6cm

7 0

11 months ago

A flagpole is 25 feet tall. A rope is tied to the top of the flagpole and secured to the ground 16 feet from the base of the fla

Lerok [7]

As for the drawing, help yourself.

P. theorem -- a^2 + b^2 = c^2
a = 25
b = 16

so 25^2 + 16^2 = c^2
c^2 = 881
c = sqrt881

8 0

3 years ago