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Lisa [10]
2 years ago
14

Line has equation 3x + y = 15 Find the gradient of the line.

Mathematics
1 answer:
inessss [21]2 years ago
5 0

Answer:

  -3

Step-by-step explanation:

We can add -3x to put the equation into slope-intercept form.

  y = -3x +15

The gradient of the line (slope) is the coefficient of x: -3.

The gradient is -3.

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Cindy and Jose were in charge of selling tickets to the class play. Cindy sold 40 tickets and Jose sold 28 tickets. What is the
FrozenT [24]

Answer:

10:17

Step-by-step explanation:

If I am making a ratio of the tickets Cindy sold to the number of tickets sold in all it would be 40:68 but I would have to simplify and 40 divided by 2 = 20 and 68 divided by 2 = 34 then I would divide them both by two again to get our answer of    10:17!   Hope this helps!  Have a great day!

4 0
3 years ago
I can’t figure out this answer I’ve gotten so many and it seems non of them work
Mandarinka [93]

The quotient is 0.20125.

Solution:

Divide .03220 by .16

This can be written as

$\frac{\cdot 03220}{\cdot 16}

To divide this, we first remove the decimal term.

To remove decimal in denominator multiply and divide by 100.

$\frac{\cdot 03220}{\cdot 16}\times \frac{100}{100}=\frac{3.22}{16}

Now, divide 3.22 by 16.

The quotient is 0.20125.

The image of the long division is attached below.

6 0
2 years ago
Can someone explain this to me? No Links no bots.
IceJOKER [234]

Answer:

Domain and Range. The domain of a function is the set of values that we are allowed to plug into our function. This set is the  values in a function such as ). The range of a function is the set of values that the function assumes. This set is the values that the function shoots out after we plug an  value in.

Step-by-step explanation:

3 0
2 years ago
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
3 years ago
What is 3/4 divided by 1/2<br><br> 2/3<br><br> 1 <br> 1 1/4<br><br> 1 1/2 <br><br> 3
Sphinxa [80]
3/4 divided by 1/2 is 1 1/2
5 0
2 years ago
Read 2 more answers
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