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sp2606 [1]
3 years ago
10

Find the equation of the line passing through the points (-1,7) and

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0
A)
slop intercept form is y=mx+b

To find m, it is (y2-y1)/(x2-x1) or (-8-7)/(2-(-1)) which then = -5

To find b, the y-intercept choose one of the points and solve for b using:
y=x(slope)+b
7= -1( -5)+b
7= 5+b
2=b (subtract 5 on both sides)

I hope this helped!
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The integers X and Y fulfil the condition 2X=5Y. Which can be considered for X+Y?
KiRa [710]

Answer:

X + Y could equal to 1 \frac{2}{5}X or 3 \frac{1}{2}Y.

Step-by-step explanation:

2X = 5Y

Y = \frac{2}{5}X

X = \frac{5}{2}Y

Hence, X + Y could equal to X + \frac{2}{5}X = 1 \frac{2}{5}X or Y + \frac{5}{2}Y = 3 \frac{1}{2}Y.

Hence, X + Y could equal to 1 \frac{2}{5}X or 3 \frac{1}{2}Y.

6 0
3 years ago
Please help me I need your help I please you to death please please please please I’m begging you for your help to death right n
vampirchik [111]

Answer:

A

Step-by-step explanation:

Don't really want you to die ^^

d = total earnings so it's the dependent/y variable

h = hours so it's the independent/x variable

9.25 = earnings per hour or slope

b = 0 since Chakan starts off with $0

Using y = mx + b...

d = 9.25h + 0 or d = 9.25h

3 0
3 years ago
I need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)
Dahasolnce [82]

Five number summary and IQR of both the data sets are different.

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Part A:

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set into four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

The interquartile range of the data is

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =16-6.2\\     =9.5

The interquartile range of the data is

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =15.5-8\\     =7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.

To learn more about the symmetric visit:

brainly.com/question/1002723

#SPJ1

6 0
2 years ago
What is equivalent to -1/3t=4/3​
stepan [7]

<u>Answer:</u>

The equivalent of -1/3t = 4/3​ is t = -4

<u>Solution:</u>

Need to determine such value of t so that when it is multiplied by -1/3, we should get 4/3

That is we need to solve following expression for value of t.

-\frac{1}{3} t=\frac{4}{3}

On multiplying both the sides by 3 we get

\begin{array}{l}{-\frac{1}{3} t \times 3=\frac{4}{3} \times 3} \\\\ {=>-t=4}\end{array}

Now multiplying both the sides by -1 we get

\begin{array}{l}{-t \times-1=4 \times-1} \\ {=>t=-4}\end{array}

Let’s recheck the value of t

-\frac{1}{3} t=-\frac{1}{3} \times-4=\frac{4}{3}

Hence for t = -4, expression -1/3 t is equal to 4/3.

6 0
3 years ago
How do you find mode in data
nikdorinn [45]

Answer:

The mode is the number that shows up most frequently

Step-by-step explanation:

Example, in the number set below

1, 1, 2, 3, 4, 4, 4, 4, 5, 7, 35, 36

The mode is 4

4 0
3 years ago
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