Answer:
Equation of line is y=(12/5)x+2
Step-by-step explanation:
The slope of line AB is -5/12. The line passing X is perpendicular to line AB and hence have a slope of 12/5. The slope intercept form is given by y=mx+c.
Now, point X satisfies the equation. Plugging in the slope of the line we end up with
y=(12/5)*x+c, now to find c
-10=(12/5)*(-5)+c, c=2
Equation of line is y=(12/5)x+2
Looks like you are screwed good luck:)
Answer: C) x = 2
2^{2x + 2} = 2^{3x}
Since both terms (above) have the same base, set the exponents to be equal:
2x + 2 = 3x (Rearrange to solve for x)
x = 2
∴ x = 2
<h3>
Answer: b = 4 and c = 7.</h3>
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Explanation:
Comparing y = x^2+bx+c to y = ax^2+bx+c, we see that a = 1.
The vertex given is (-2,3). In general, the vertex is (h,k). So h = -2 and k = 3.
Plug those three values into the vertex form below
y = a(x-h)^2 + k
y = 1(x-(-2))^2 + 3
y = (x+2)^2 + 3
Then expand everything out and simplify
y = x^2+4x+4 + 3
y = x^2+4x+7
We see that b = 4 and c = 7.
