All categories

2 years ago

Determine the range of the following graph:

Mathematics

1 answer:

Allushta [10]2 years ago

8 0

Answer:

Determine the range of the following graph:

Step-by-step explanation:

(f+g)(x)

f(x)= x-3, g(x)= 2x+8

You might be interested in

What is the constant rate of change from the graph? <br> 2 <br> 10 <br> 5 <br> 1/5

Dvinal [7]

I believe the answer is 0.5

3 0

4 years ago

(05.08A)Triangle ABC is transformed to similar triangle A′B′C′ below:

Romashka-Z-Leto [24]

Answer:

1st option is correct i.e., 1 over 2

Step-by-step explanation:

Given that Triangle ABC transformed to Triangle A'B'C'.

Coordinated of Triangle ABC are A(2,6) , B(2,4) and C(4,4)

Coordinated of Triangle A'B'C' are A'(1,3), B'(1,2) and C'(2,2)

Scale factor of Dilation is the no. of times coordinates of vertices of a figure increase or decrease.i.e.,

if A(a,b) ⇒ A'(c,d)

where, a.k=c & b.k=d then k is scale factor of dilation.

Value of k is same for all vertices.

For coordinates of A & A' ,we have $2.k=1\implies k=\frac{1}{2} \:\: and \:\: 6.k=3\implies k=\frac{1}{2}$

For coordinates of B & B' ,we have $2.k=1\implies k=\frac{1}{2} \:\: and \:\: 4.k=2\implies k=\frac{1}{2}$

For coordinates of C & C' ,we have $4.k=2\implies k=\frac{1}{2} \:\: and \:\: 4.k=2\implies k=\frac{1}{2}$

Therefore, the scale factor of dilation is $\:\frac{1}{2}\:$ since in all cases $k=\frac{1}{2}$

1st option is correct i.e., 1 over 2

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%3D1%2F3%284-x%29%C2%B2%20what%20is%20the%20value%20of%20f%2816%29" id="TexFormula1" t

STALIN [3.7K]

Answer:

wheneveryouseeanxonthe

rightputa16thatwhatf(16)

means.

f(16)=

(4−16)

f(16)=

(−12)

f(16)=

(144)

f(16)=48

[isyouranswer]

Step-by-step explanation:

mark me as brainliest.oky?

6 0

3 years ago

Complete the function table and write the function rule.

arsen [322]

To finish the table lets see what the differences are between the input (x) and the output (Y)

when input is 32 the output is 20, 32-20 = 12
when input is 14 the output is 2, 14-2 = 12

since the top 2 have the same result, the output is the input minus 12
now that we know that we can finish the table:

when the input is ? the output is -6, so the input = -6 +12 = 6
check: 6-12 = -6 true

when the input is -10, we subtract 12 to get -22 for the output
so the missing input is 6 and the missing output is -22

the function rule would be Y=x-12

6 0

3 years ago

HELPPP!!!! Both questions are incredibly confusing to me !!!!!

Darya [45]

Answer:

Step-by-step explanation:

I'm going to start with problem 3. You need to become familar with the kind of tricks teachers play on you.

Problem 3 depends on getting RS = RW.

RT = RT Reflexive property

<STR = <WTR A straight line having 1 rt angle actually has 2

ST = TU They are marked as equal

Triangle STR=Triangle WTR SAS

RS = RW Corresponding parts of = triangles are =

8x = 6x + 5 Subtract 6x from both sides

8x -6x = 6x - 6x + 5 Combine

2x = 5 Divide by 2

2x/2 = 5/2

x = 2.5

RU = 6*2.5 + 5

RU = 15 + 5

RU = 20

Now we can play with Question 4.

This question depends on the method used in three, although not entirely.

What you need to know is that W is on RT when you take a ruler and make RT longer. You can put W anywhere as long as it is on RT when it is made longer.

Directions

Make RT longer. Draw down and to your right.

Put a point anywhere on the length starting at T. Label this new point as W. There's your W. It goes anywhere on the part of RT made longer.

Draw UW.

Label UW as 8

Now draw another line from S to W. Guess what? By the methods used in question 3, it's also 8. So SW = 8

TW = TW Reflexive

<UTW = STW Same reason as in 3. UtW is a right angle

UT = ST Given (the marking tells you so.

ΔUTW = ΔSTW SAS

UW = SW Corresponding parts of = triangles are =

SW = 8

7 0

3 years ago