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3 years ago

11

How can you find 72-25? circle all the correct answers

2 answers:

Delvig [45]3 years ago

5 0

Answer:

eeeeeeeeeeeeeeeeeeeeeeeeeeeee

Step-by-step explanation:

Serggg [28]3 years ago

3 0

You can find it by doing out the math and the equation

You might be interested in

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

<u>case b)</u> $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

<u>case c)</u> $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

<u>case d)</u> $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

$x^{2}-2x-4=0$

5 0

3 years ago

Read 2 more answers

1) Solve the inequality.<br> 8x + 9 < 4x - 3

Nitella [24]

Answer:

x < -3

Step-by-step explanation:

subtract 4x: 4x + 9 < -3

subtract 9: 4x < -12

divide by 4: x < -3

3 0

3 years ago

Use logarithmic properties and the fact that ln(2) ≈ 0.69 and ln(3) ≈ 1.10 to approximate the value of each of the

leva [86]

Answer:

The answer is 0.97

Step-by-step explanation:

Hi, we need to use the log properties taking into account that Ln(2) is aprox. 0.69 and Ln(3) is aprox. 1.10. I think you can understand better as we solve it, so here it goes.

$Ln(\frac{8}{3} )=Ln(8)-Ln(3)$

Since:

$8=2^{3}$

$Ln(2^{3} )-Ln(3)$

Then

$3Ln(2)-Ln(3)$

Now, we have everything where we want it, in terms of Ln(2) and Ln(3), now it is easy to solve.

$3(0.69)-1.10$

$2.07-1.10=0.97$

Best of luck.

5 0

3 years ago

35/27 as a mixed number

sineoko [7]

8/27 would be the answer

5 0

3 years ago

Please I really need ur help !!!

AURORKA [14]

It’s B hope this helps

6 0

3 years ago