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guapka [62]
3 years ago
14

Please help. I’ll mark you as brainliest if correct!

Mathematics
1 answer:
In-s [12.5K]3 years ago
8 0

Answer:

8

Step-by-step explanation:

f^-1(x) =dy/dx

dy/dx(8x+9)=8

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Solve x2 – 64 = 0. Isolate x2: x2 = 64 Apply the square root property of equality: Isolate the variable: x = x =
dybincka [34]
Solve the equation by isolating the variable you're solving for on one side of the equation and get everything on the opposite side.

x^2 - 64 = 0

The x variable is being square and is being subtracted by 64.
Find the inverse of all of these operations.

First, get rid of the subtraction operation. The inverse of subtraction is addition.

Add 64 to both sides of the equation.

x^2 - 64 + 64 = 0 + 64 \\ x^2 = 64

Now the variable x is only being squared. Reverse this operation by using the inverse of exponents.

Take the square root of both sides.

\sqrt{x^2} = \sqrt{64}  \\ x = 8

So, x is equal to 8.
6 0
4 years ago
Read 2 more answers
Can i have some help with this?
irina [24]

Answer:

10.75 cm^2

Step-by-step explanation:

1. Area of semicircle, A= (pi x R^2) divided by 2

2. A= (3.14 x 5^2) divided by 2 = 39.25

3. Area of rectangle, A= l x w

4 A= 10 x 5 = 50

5. subtract

6. 50 - 39.25

7. 10.75

6 0
3 years ago
Ursula likes to kayak. She uses the equation y=4x to calculate how far she has traveled, where y represents the number of miles
KIM [24]
Hopefully this helps you get how to set up these types of problems

5 0
3 years ago
Read 2 more answers
What is the value of the expression below when y = 5?
muminat

Answer:

56

Step-by-step explanation:

10y+6

10(5)+6

10*5=50

50+6=56

3 0
3 years ago
Read 2 more answers
Work out the m and c for the line<br> y=x+6
VARVARA [1.3K]

Answer:

m - 1

c - 6

Step-by-step explanation:

y=x+6\\\\

The equation is in slope-intercept form.

y = mx + c

m - slope

c (or b) - y -intercept

Usually if the slope is one it will not be written.

y = 1x + 6  

The slope is one.

6 takes 'c's place, so it is the y-intercept.

Hope this helps.

4 0
3 years ago
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