Reasons

Mathematics

1 answer:

kenny6666 [7]3 years ago

6 0

Answer:

Reasons 1. Given

2. Angle Addition Postulate

Statements

1. AD|| BC

2. mZ3+m25 mZDAB

3. m24+mZDAB = 180*

4. m24+mZ3+ m25 180°

5. 21 $ 24, 22 & 25

6. mZ1 m24, m22 m25

7. mZ1+m/2+mZ3 180°

3. Linear Pair Postulate

4. Substitution Property of Equality

15.

6. Definition of Congruent Angles

The

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<img src="https://tex.z-dn.net/?f=%28y%20-%201%29%28y%20%2B%203%29" id="TexFormula1" title="(y - 1)(y + 3)" alt="(y - 1)(y + 3)"

m_a_m_a [10]

Sense there's only a y, you'd assume y is 1 or 1y.

you'd make the 1 a negative 1 to get rid of the subtraction sign.

you'd add together the 2 ys making it 2y. then add -1 + 3, which would be 2.

so, the answer would be 2y + 2.

7 0

3 years ago

The proof that point (1,root 3) lies on the circle that is centered at the origin and contains the point (0,2) is found in the t

AURORKA [14]

<h2>Answer:</h2>

D. Distance formula

<h2>Step-by-step explanation:</h2>

$The \ \mathbf{distance} \ d \ between \ the \ \mathbf{points} \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ in \ the \ plane \ is:\\ \\ d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

As in the statement:

<em>The distance form</em> $(0,0)$ to $(0,2)$ is $\sqrt{(0-0)^2+(2-0)^2}=\sqrt{2^2}=2$ <em>whose justification is the </em><em>Distance Formula. </em>

<em />

Here in this statement the justification is also the Distance Fromula, so we take the distance from $(0,0) \ to \ (1,\sqrt{2})$ whose result is also 2 and is the radius of the circle.