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docker41 [41]
3 years ago
14

Are 4 7/9 and repeating 4.7 are they equal?

Mathematics
1 answer:
cluponka [151]3 years ago
4 0

Answer:

Step-by-step explanation:

These two expressions are definitely not equal.

4 7/9 is a repeating decimal:  4.77777 ...    (use your calculator)

whereqs 4.7 is NOT a repeating decimal.

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What is 3/4 -7/10 -3/4 and 8/10 In order from least to greatest
zaharov [31]
-3/4, -7/10, 3/4, 8/10 is least to greatest
3 0
3 years ago
Read 2 more answers
Jeff writes comic strips for a local newspaper. The number of comic strips he creates is represented by the function f(x) = 3x,
Andrei [34K]
If he does three hours, its 9 strips, for four, its 12, six is 18, seven is 21, and nine is 27
7 0
3 years ago
if a rectangle has am area of 2x²+11x+15, what would be an expression for the length, and for the width?
lozanna [386]

Answer:

Length = 2x + 5

Width = x + 3

Step-by-step explanation:

Area of rectangle = length × width

Expression for area of the rectangle = 2x² + 11x + 15

Factorising the quadratic expression

2x² + 11x + 15 = 2x² + 6x + 5x + 15 = (2x² + 6x) + (5x + 15) = 2x(x + 3) +5(x + 3) = (2x + 5)(x + 3)

Length = 2x + 5

Width = x + 3

3 0
3 years ago
Here's the question: You have an electrical circuit with various components, all of which are in series. The current (I) through
vredina [299]

Answer:Magnitude of voltage is 41.9963 volts


Step-by-step explanation:

Given that current I =5.772-5.323i mA

          and impedance, Z=3.342+4.176i kilo ohms

Then voltage in the circuit = IZ

                                            =(5.772-5.323i)X10^{-3}X(3.342+4.176i)X10^{3}

                                      V=(5.772-5.323i)X(3.342+4.176i)

                                      V=19.290024+24.103872i-17.789466i-23..5148848i^{2}

                                     V=41.518892+6.314406i

Magnitude of V = \sqrt{41.518892^{2} +6.314406^{2} }=\sqrt{1763.6901}=41.9963volts


7 0
3 years ago
Help! You can look at the picture please
viva [34]

Answer:

\frac{3x}{3 - 2x}

Step-by-step explanation:

Here,

f(x) = y

y =  \frac{3x}{2x + 3}

or , swapping x with y

x =  \frac{3y}{2y + 3}

now to solve for y we get

y =  \frac{3x}{3 - 2x}

now we put f inverse x instead of y

{f}^{ - 1} (x) =  \frac{3x}{3 - 2x}

I am done.

4 0
3 years ago
Read 2 more answers
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