Answer:
A regular polygon is a polygon with sides of equal length. Some examples include, a equilateral triangle, square, regular pentagon, regular hexagon, regular heptagon, regular octagon, regular nonagon, regular decagon...
The diagonal of a rectangle = sqrt(w^2 + l^2)
w = width
l = length
In this problem,
The diagonal = 20 in
w = x
l = 2x + 8
Let's plug our numbers into the formula above.
20in = sqrt((x)^2 + (2x + 8)^2)
Let's simplify the inside of the sqrt
20 in = sqrt(5x^2 + 32x + 64)
Now, let's square both sides.
400 = 5x^2 + 32x + 64
Subtract 400 from both sides.
0 = 5x^2 + 32x - 336
Factor
0 = (5x - 28)(x + 12)
Set both terms equal to zero and solve.
x + 12 = 0
Subtract 12 from both sides.
x = -12
5x - 28 = 0
Add 28 to both sides.
5x = 28
Divide both sides by 5
x = 28/5
The width cant be a negative number so now we know that the only real solution is 28/5
Let's plug 28/5 into our length equation.
Length = 2(28/5) + 8 = 56/5 + 8 = 96/5
In conclusion,
Length = 96/5 inches
Width = 28/5
Answer:
The new can can hold upto volume of 476.69 cubic centimeters.
Step-by-step explanation:
Diameter of the can = d = 6 cm
Radius of the can = r = 0.5d = 0.5 × 6 cm = 3 cm
Height of the can = h = 12 cm
Company wants to increase the dimensions of their cans by a multiple of 1.12. So, the new dimension will be:
r'= 3 cm × 1.12 = 3.36 cm
h' = 12 cm × 1.12 =13.44 cm
Volume of the = can = V
Volume of a cylinder = 
The new can can hold upto volume of 476.69 cubic centimeters.
