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nignag [31]
3 years ago
9

Which shows 532 − 472 being evaluated using the difference of squares method? 532 − 472 = 2809 − 2209 = 600 532 − 472 = (53 + 47

)(53 − 47) = (100)(6) = 600 532 − 472 = (53 − 47)2 = 62 = 36 532 − 472 = (2809 + 2209)(2809 − 2209) = 3,010,800
Mathematics
2 answers:
docker41 [41]3 years ago
8 0
I guess you mean 53^2 - 47^2
Its best to use the '^' symbol to avoid confusion.

the second choice is the correct one.
AnnyKZ [126]3 years ago
4 0

For this case we have that by definition, the difference of squares is given by:

a ^ 2 - b ^ 2 = (a + b) (a-b)

We then have the following expression:

53 ^ 2 - 47 ^ 2

According to the definition, we rewrite as:

53 ^ 2 - 47 ^ 2 = (53 + 47) (53-47)

Then, rewriting we have:

53 ^ 2 - 47 ^ 2 = (100) (6)\\53 ^ 2 - 47 ^ 2 = 600

Answer:

Option B

53 ^ 2 - 47 ^ 2 = (53 + 47) (53-47) = (100) (6) = 600


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Answer:

6 cm

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A = 1/2(b + 12)(4)

36 = 1/2(b + 12)(4)

72 = (b + 12)(4)

18 = b + 12

18 - 12 = b

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or

b = 6 cm

3 0
3 years ago
A man gets $80 for 5 days work.how much does he get for 14 days work?sho all working
stich3 [128]
Ok so we can state that for 5 days he gets 80 dollats meaning that for 1 day he should get 16 dollars i.e
80 dollars -> 5 days
80/5 = 16
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Hope this helps :).

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6 0
4 years ago
Select the perfect square trinomial from among the options below.
Leokris [45]
Answer : A
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4 0
3 years ago
Read 2 more answers
What is the value of x?
maw [93]
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8 0
3 years ago
What are the answers to all of these questions?
VikaD [51]
We have that

N 11)
a) graph the equation  y=x²-3x-10

using a graph tool
see the attached figure

b) Determine the roots of the equations
the roots of the equations are the values for y=0
x²-3x-10=0
x²-3x-10=(x+2)*(x-5)=0
the roots are
x1=-2
x2=5

see the attached figure problem 11

N 12) what is the value of x in the equation? 
3x²=7x

3x²=7x-------> 3x²-7x=0--------> x*(3x-7)=0

x1=0
3x-7=0------> 3x=7------> x=7/3

the values of x are
x1=0
x2=7/3---> 2.33
see the attached  figure problem 12

N 13) what is the value of x in the equation? 
x²-5x=6----------> x²-5x-6=0
x²-5x-6=0-------> (x+1)*(x-6)=0
the values of x are
x1=-1
x2=6

N 14) what is the value of x in the equation? 
2x²-5x=12--------> 2x²-5x-12=0

using a graph tool
see the attached figure problem N 14
2x²-5x-12=0----------> (x+3/2)*(x-4)=0

the values of x are
x1=-3/2
x2=4



7 0
3 years ago
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