D
C
B
D
Hope I helped!
Giving me brainliest is much appreciated! =)
Answer:
7.3% percentage of the bearings produced will not be acceptable.
Step-by-step explanation:
Consider the provided information.
Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.
Let X is the normal random variable which represents the diameter of bearing.
Thus, 0.500-0.004<X<0.500+0.004
0.496<X<0.504
The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.
Use the Z score formula:
Therefore
Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.
We need to find the percentage of the bearings produced will not be acceptable.
So subtract it from 1 as shown.
1-0.9270=0.073
Hence, 7.3% percentage of the bearings produced will not be acceptable.
F(X) means plug in te number within the parenthesis for the given function. It's simply an equation expressed through different notation. In this case it asks you to plug in two, so you do:
-3(2)+4 = f(2)
That means that f(2)=-2.
Answer:
In the operation, simplify
9-a² = (3-a)(3+a)
Factorize
4a²-4a-24-------------------divide each term by 4
a²-a-6-------------------------factorize
a²-3a+2a-6
a(a-3)+2(a-3)
(a+2)(a-3)
Factorize
a²-6a+9
a²-3a-3a+9
a(a-3)-3(a-3)
(a-3)(a-3)
Rewrite operation as
Multiply by the recipricol
cancel the similar terms
Answer:
F
Step-by-step explanation:
its the only one that makes sense! hope this helps! :D