Find the equation of the line that is perpendicular to y = – 1 3 x + 2 and passes though the point (–5, 2).
1 answer:
Answer:
Step-by-step explanation:
eq . of line is y=-13 x+2
or 13 x+y=2
eq. of any line perpendicular to above line is
x-13y=c
because it passes through (-5,2)
-5-13(2)=c
c=-31
x-13y=-31
13y=x+31
y=1/13 x +31/5
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