Answer:
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Class 11
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>>Units and Measurement
>>Errors in Measurement
>>You measure two quantities ...
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You measure two quantities as A=1.0m±0.2m, B=2.0m±0.2m. We should report correct value for
AB
as
Medium
Solution
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Correct option is
D
1.4m±0.2m
Here, A=1.0m±0.2m, B=2.0m±0.2m
AB=(1.0m)(2.0m)=2.0m
2
AB
=
2.0m
=1.414m
Rounding off to two significant figures, we get
AB
=1.4m
AB
ΔAB
=
2
1
(
A
ΔA
+
B
ΔB
)=
2
1
(
1.0
0.2
+
2.0
0.2
)=
2
0.3
Δ
AB
=
2
0.3
×
AB
=
2
0.3
×1.414=0.212m
Rounding off to one significant figure, we get
Δ
AB
=0.2m
The correct value for
AB
is 1.4m±0.2m
Answer:
exact form: -17/8
decimal form: -2.125
mixed number form: -2 1/8
Step-by-step explanation:
cmon this is freaking addition
Answer: 0.9738
Step-by-step explanation:
This is solved by the probability distribution formula for random variables where probability of determining random variable X is given by
P(X=r) = nCr * p^r * q^n-r
Where n = number of sample = 6
p = probability of success = 0.545
q = 1-p = 0.455
r = possible outcome from number of sample.
If 6 random births are chosen, Probability that at least 1 of them is a girl = 1 -[probability that none of them is a girl] = 1 - [probability that all 6 kids are boys]
Probability that all 6 kids are boys = 6C6 * 0.545^6 * 0.455^0 = 0.0262
Probability that at least one is a girl = 1 - 0.0262 = 0.9738.
Answer:
2.5
Step-by-step explanation:
Answer:
4^0
Step-by-step explanation:
whenever the number is to the power of 0 it equals 1
4^5 x 4^-7 ÷ 4^-2 = 1
4^0 = 1