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beks73 [17]
2 years ago
11

Is the sum of two rational numbers always rational

Mathematics
1 answer:
Pepsi [2]2 years ago
8 0

Answer:

in short, Yes they are always rational.

here's why...

E.g. suppose \frac{c}{d} and \frac{a}{b} are fractions, that means that a,b,c,d are all integers, and b and d are not zero. finding the sum the numerator, and denominator would also have to be integers. the denominator of the sum can't be zero since the denominators of the fractions were not zero, and would give \frac{ad+bc}{bd} and since they are bound by addition (sum means addition) they must also be rational since eit would equal a bigger integer than initially had

Step-by-step explanation:

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I'll give brainliest and points to whomever answers these two questions, thank you so much in advance!
podryga [215]

Answer:

Answer b of the first one

answer of q9

Step-by-step explanation:

(x+iy)(2−3i)=4+i

2x−(3x)i+(2y)i−3yi

2

=4+i

Real

2x+3y

​

​

+

Imaginary

(2y−3x)

​

​

i=4+i

Comparing the real & imaginary parts,

2x+3y=4--------------------------(1)

2y−3x=1----------------------------(2)

Solving eq(1)  &  eq(2),

4x+6y=8

−9x+6y=3

13x=5⇒x=

13

5

​

y=

13

14

​

∴(x,y)=(

13

5

​

,

13

14

​

)

Was this answer helpful?

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23

SIMILAR QUESTIONS

star-struck

If e

x+iy

=α+iβ, then x+iy is called logarithm of α+iβ to the base e.∴log

e

​

(x+iy)=log

e

​

(re

iθ

) =log

e

​

r+iθ where r is modulus value of x+iy & θ be the argument of x+iy If i

α+iβ)

=α+iβ, then α

2

+β

2

 equals

Hard

View solution

>

The modulus of (1 + i) (1 + 2i) (1 + 3i) is equal to

3 0
2 years ago
Read 2 more answers
What is the absolute value of 2 and 1 therds
sleet_krkn [62]

Answer: 2 and 1 thirds is the answer

Step-by-step explanation:

This is the answer because the absolute value mean how much places the number is away from 0 so 2 1/3 is 2 1/3 away from zero.

7 0
3 years ago
The increasing annual cost (including tuition, room, board, books, and fees) to attend college has been widely discussed (Time).
NeX [460]

Answer:

(a) PRIVATE COLLEGES

Sample mean is $42.5 thousand

Sample standard deviation is $6.65 thousand

PUBLIC COLLEGES

Sample mean is $22.3 thousand

Sample standard deviation is $4.34 thousand

(b) Point estimate is $20.2 thousand. The mean annual cost to attend private colleges ($42.5 thousand) is more than the mean annual cost to attend public colleges ($22.3 thousand)

(c) 95% confidence interval of the difference between the mean annual cost of attending private and public colleges is $19.2 thousand to $21.2 thousand

Step-by-step explanation:

(a) PRIVATE COLLEGES

Sample mean = Total cost ÷ number of colleges = (51.8+42.2+45+34.3+44+29.6+46.8+36.8+51.5+43) ÷ 10 = 425 ÷ 10 = $42.5 thousand

Sample standard deviation = sqrt[summation (cost - sample mean)^2 ÷ number of colleges] = sqrt([(51.8-42.5)^2 + (42.2-42.5)^2 + (45-42.5)^2 + (34.3-42.5)^2 + (44-42.5)^2 + (29.6-42.5)^2 + (36.8-42.5)^2 + (51.5-42.5)^2 + (43-42.5)^2] ÷ 10) = sqrt (44.24) = $6.65 thousand

PUBLIC COLLEGES

Sample mean = (20.3+22+28.2+15.6+24.1+28.5+22.8+25.8+18.5+25.6+14.4+21.8) ÷ 12 = 267.6 ÷ 12 = $22.3 thousand

Sample standard deviation = sqrt([(20.3-22.3)^2 + (22-22.3)^2 + (28.2-22.3)^2 + (15.6-22.3)^2 + (24.1-22.3)^2 + (28.5-22.3)^2 + (22.8-22.3)^2 + (25.8-22.3)^2 + (18.5-22.3)^2 + (25.6-22.3)^2 + (14.4-22.3)^2 + (21.8-22.3)^2] ÷ 12) = sqrt (18.83) = $4.34 thousand

(b) Point estimate = mean annual cost of attending private colleges - mean annual cost of attending public colleges = $42.5 thousand - $22.3 thousand = $20.2 thousand.

This implies the the mean annual cost of attending private colleges is greater than the mean annual cost of attending public colleges

(c) Confidence Interval = Mean + or - Margin of error (E)

E = t×sd/√n

Mean = $42.5 - $22.3 = $20.2 thousand

sd = $6.65 - $4.34 = $2.31 thousand

n = 10+12 = 22

degree of freedom = 22-2 = 20

t-value corresponding to 20 degrees of freedom and 95% confidence level is 2.086

E = 2.086×$2.31/√22 = $1.0 thousand

Lower bound = Mean - E = $20.2 thousand - $1.0 thousand = $19.2 thousand

Upper bound = Mean + E = $20.2 thousand + $1.0 thousand = $21.2 thousand

95% confidence interval is $19.2 thousand to $21.2 thousand

6 0
3 years ago
Find the value of x that makes m<br> n.<br> m<br> n<br> (180 - x)^
enot [183]

Answer:

x=180-x

2x=180

x=90

Step-by-step explanation:

3 0
2 years ago
Write the formula of the function y whose graph is show.
elena-14-01-66 [18.8K]

Answer:

im on the same question

7 0
3 years ago
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