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2 years ago

Which of the following may be allowed in a food preparation area.

SAT

1 answer:

AVprozaik [17]2 years ago

5 0

Among the listed items, the one that may be allowed in a food preparation area is;

Wedding Band.

Food preparation can be regarded as the process of preparing food which may involve cooking and other activities.

However,, the place of cooking should be hygienic and contaminating items should be do away with.

Therefore, Among the listed items, the one that may be allowed in a food preparation area is;

Wedding Band.

CHECK THE COMPLETE QUESTION BELOW;

the one that may be allowed in a food preparation area: Smoking, Chewing Gum, Pets, Wearing a Wedding Band

Learn More about food preparation at;

brainly.com/question/25705073

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2 years ago

For the galvanic (voltaic) cell fe(s) + mn²⁺(aq) ⟶ fe²⁺(aq) + mn(s) (e° = 0.77 v at 25°c), what is [fe²⁺] if [mn²⁺] = 0.050 m an

Nuetrik [128]

The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.

<h3>What is the Nernst Equation?</h3>

The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:

$\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}$

where;

n = Number of electrons = 2
$\mathbf{E_o}$ = Initial voltage = 0.77 V
$\mathbf{E_{cell}}$ = Cell voltage = 0.78 V
$\mathbf{[Mn^{2+}]}$ = Manganese concentration = 0.050 M

Replacing the values into the above equation, we have:

$\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}$

$\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}$

$\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}$

$\mathbf{Fe^{2+} = (0.4594\times 0.050 )\ M}$

$\mathbf{Fe^{2+} =0.02297 \ M }$

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2 years ago

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