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alexira [117]
2 years ago
14

Select the correct answer. help

Mathematics
1 answer:
Archy [21]2 years ago
4 0

Answer:

Option D.

See the image I have attached with the answer.

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What is the molar mass of tetraethyl lead, Pb(C2H5)4? show your work please
Mars2501 [29]
M(Pb(C2H5)4 = M(PB)*1 + 4*( M(C)*2 + M(H)*5)
M(Pb(C2H5)4 = 207.2 + 4(12.0*2 + 1.0*5)
M(Pb(C2H5)4 = 207.2 + 4(28.0 + 5)
M(Pb(C2H5)4 = 207.2 + 4*33
M(Pb(C2H5)4 = 207.2 + 132
M(Pb(C2H5)4 = 339.2 g/mol

Hope this helps !

Photon

4 0
4 years ago
On a standard IQ test, the standard deviation is 15. How many random IQ scores must be obtained if we want to find the true popu
igor_vitrenko [27]

Answer:

We need at least 4238 scores.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.97}{2} = 0.015

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.015 = 0.985, so z = 2.17

Now, find the margin of error M

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How many random IQ scores must be obtained if we want to find the true population mean (with an allowable error of 0.5) and we want 97 percent confidence in the results

We need at least n scores, in which N is found when M = 0.5. So

M = z*\frac{\sigma}{\sqrt{n}}

0.5 = 2.17*\frac{15}{\sqrt{n}}

0.5\sqrt{n} = 2.17*15

0.5\sqrt{n} = 32.55

\sqrt{n} = \frac{32.55}{0.5}

\sqrt{n} = 65.1

\sqrt{n}^{2} = (65.1)^{2}

n = 4238

We need at least 4238 scores.

7 0
4 years ago
According to the law of conservation of mass, in all chemical reactions _____.
myrzilka [38]

Answer:

The mass of all products must be equal to the mass of the reactants.

Step-by-step explanation:

<h2><u>Fill in the blanks </u></h2>

--According to the law of conservation of mass, in all chemical reactions<u> the mass of all products must be equal to the mass of the reactants.</u>

4 0
3 years ago
Mrs. Adenan sold 63 bracelets at one craft fair and 36 bracelets at a second craft fair. Which expression correctly applies the
stellarik [79]
63 + 36...there is a common factor of 9
9(7 + 4) <== this is equivalent

63 + 36...there is a common factor of 3
3(21 + 12)...but this is not an answer choice...but it is equivalent
7 0
4 years ago
A population has the following characteristics.(a) A total of 25% of the population survives the first year. Of that 25%, 75% su
zaharov [31]

Answer:

After 1st year, the age distribution will be

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right]

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

x_1 = A \cdot x

x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = A \cdot x_1

x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

4 0
4 years ago
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