Write and solve a system of equations made up of Aiden's and Natalie's lines of best fit that they can use

Mathematics

1 answer:

dezoksy [38]3 years ago

7 0

The catapult arm length for their tennis balls to cover the same distance is 32.3 feet.

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

Given the equations:

Aiden: y = 2.3x + 160.7

Natalie: y = 3.6x + 202.6

For their tennis balls to cover the same distance:

2.3x + 160.7 = 3.6x + 202.6

1.3x = -41.9

x = -32.3

The catapult arm length for their tennis balls to cover the same distance is 32.3 feet.

Find out more on linear equation at: brainly.com/question/14323743

You might be interested in

Ajax is 5 and 1 fourth feet tall. His sister is 3 eighths foot shorter than Ajax How tall is Ajax Sister?

user100 [1]

Answer:

$4\frac{3}{4}$ feet tall

Step-by-step explanation:

Ajax is "5 and 1 fourth feet tall", which can be written as the mixed number $5\frac{1}{4}$ .

His sister is "3 eighths foot shorter", so she's 3/8 feet shorter than 5 1/4.

So, this is just a subtraction problem:

$5\frac{1}{4} -\frac{3}{8}$

To solve this, we want to convert 5 1/4 into an improper fraction, which is: $\frac{21}{4}$ . Now, we want to find a common denominator. In this case, that common denominator is 8, so $\frac{21}{4} =\frac{42}{8}$ .

Finally, we subtract 3/8 from 42/8: $\frac{42}{8} -\frac{3}{8} =\frac{39}{8}$ . So, Ajax's sister is 39/8 feet. Converting this into a mixed number, we have: 39/8 = 4 $\frac{6}{8} =4\frac{3}{4}$ .

Therefore, Ajax's sister is $4\frac{3}{4}$ feet tall.

Hope this helps!

7 0

3 years ago

Read 2 more answers

The student council had a canned food drive. They collected a total a total of 63 cans on Wednesday. This is 21% of the total ho

Alex73 [517]

We are told that 21% of the total cans is 63 cans, therefore
100% of all the cans collected would be.

(63*100)/21=300 cans were collected in all

4 0

3 years ago

find the perimeter and diagonal of a square whose area is equal to the area of a rectangle whose length is 9m and breadth is 4m

aalyn [17]

$Area\ of\ a\ rectangle:A_{\fbox{ }}=9m\times4m=36m^2\\\\a-side\ of\ a\ square\\\\Area\ of\ a\ square:A_{\fbox{}}=a^2\\\\A_{\fbox{ }}=A_{\fbox{}}\Rightarrow a^2=36m^2\Rightarrow a=\sqrt{36m^2}\Rightarrow a=6m\\\\Perimeter\ of\ the\ square:P=4a\Rightarrow P=4\times6m=\boxed{24m}\\\\Diagonal\ of\ the\ square:d=a\sqrt2\Rightarrow d=\boxed{6\sqrt2\ m}$