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wel
2 years ago
9

Find the mean (average) of the set of numbers. 12 , 6 , 7 , 19 , 12 , 3 , 3

Mathematics
1 answer:
riadik2000 [5.3K]2 years ago
7 0

Answer:

10

Step-by-step explanation:

To figure the mean, add up the numbers, 3+3+6+7+9+12+12+19=71 then divide it by the number of data points 71/7=10.1428571, I rounded it to 10.

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Please Help!!!! Solve For L
Sonja [21]
<h3>Given :</h3>

  • \tt B = L - L a f

<h3>To Find :</h3>

  • L = ?

<h3>Solution :</h3>

\tt B = L - L a f

By taking L common from \tt (L - L a f), we get :

\tt : \implies B = L(1 - a f)

\tt : \implies \dfrac{B}{(1 - a f)} = L

\tt : \implies L = \dfrac{B}{1 - a f}

Hence, value of \tt L = \dfrac{B}{1 - a f}

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Which impact did new consumer goods have on the lives of Texans in the 1920's?
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Answer:

Consumption in the 1920s The prosperity of the 1920s led to new patterns of consumption, or purchasing consumer goods like radios, cars, vacuums, beauty products or clothing. The expansion of credit in the 1920s allowed for the sale of more consumer goods and put automobiles within reach of average Americans.

Step-by-step explanation:

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It would be helpful if you show me the figure. Thanks :) !!

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2 years ago
Find the ratio of 3 3/4 to 7 1/4
Sergio039 [100]

Answer:

  15 : 29

Step-by-step explanation:

  (3 3/4) / (7 1/4) = ((3·4+3)/4) / ((7·4+1)/4)

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The ratio of the two numbers is 15 : 29.

5 0
2 years ago
Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
3 years ago
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