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ryzh [129]
3 years ago
14

If f(x)=3x+5 and g(x)=x-1,then f[g(0)]

Mathematics
2 answers:
Minchanka [31]3 years ago
5 0
F(g(x)) = 3(x-1)+ 5
F(g(0)) = 3(0-1)+5
= -3+5
= 2
viva [34]3 years ago
4 0
The answer is:  " 2" . 
___________________________________________
Answer:  " f[g(0)] = 2 " .
___________________________________________
Explanation:
___________________________________________
Given:  " f(x) = 3x + 5" ;  and:  " g(x) =x <span>− 1" ;   
</span>
Question to solve:  "What is:  f[g(0)]  ? "   ;
__________________________________________
What is "ef" of "gee" of "zero"? 
__________________________________________
Let us begin by finding "g(0)" ;

Given:  " g(x) = x − 1 " ;

To find:  " g(0) " ;  we plug in "0" for all values of "x" <span>; and</span> solve; as follows:

→  " g(0) = 0 − 1 = -1 " ;

→ So;  " g(0) = -1 " .
_______________________________________________________
We are asked to find:  " f[g(0)] " ;  

which is:  " f(-1) " .

Given:  "f(x) = 3x + 5"  ;   

→  To find " f(-1)" ;  we plug in:  "-1" for all values of "x" ;  and solve; as follows:

→  " f(-1) = 3(-1)  + 5  =  -3 + 5 = 2 .
____________________________________________________
The answer is:  " 2" . 
____________________________________________________
Answer:  " <span>f[g(0)] = 2 " . 
____________________________________________________</span>
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What are the possible pairs of numbers that have an LCM of 72
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Answer:

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Step-by-step explanation:

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3 years ago
point O lies in the interior of angle MNP. if the measure of MNO is x^2 + 10x, the measure of ONP is x^2 - 2x , and the measure
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Answer:

x = 6; ∠ONP = 24°

Step-by-step explanation:

1. Find the value of x

\begin{array}{rcl}\angle MNP & = & \angle MNO + \angle ONP\\3x^{2} + 12 & = & x^{2} + 10x + x^{2} - 2x\\3x^{2} + 12 & = & 2x^{2} + 8x\\x^{2} + 12 & = & 8x\\x^{2} -8x + 12 & = & 0\\(x - 2)(x - 6) & = & 0\\\end{array}

x = 2 \text{ or }x = 6

2. Find the measures of the angles

(a) x = 2

∠ ONP = x² - 2x = 2² - 2(2) = 4 - 4 = 0

This answer does not make sense because O lies in the interior of ∠MNP.

We disregard x = 2.

(b) x = 6

∠ ONP = x² - 2x = 6² - 2(6) = 36 - 12 = 24

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4 years ago
Find the distance between the points (0, 10) and (–9, 1).
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\\ \sf\longmapsto \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\\ \sf\longmapsto \sqrt{(-9-0)^2+(1-10)^2}

\\ \sf\longmapsto \sqrt{(-9)^2+(-9)^2}

\\ \sf\longmapsto \sqrt{81+81}

\\ \sf\longmapsto \sqrt{162}

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