Quadrilateral PQRS was translated 5 units to the right and 3 units up to create
1 answer:
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Answer:
c) Is not a property (hence (d) is not either)
Step-by-step explanation:
Remember that the chi square distribution with k degrees of freedom has this formula
Where N₁ , N₂m .... are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.
Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true
The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.
Answer to A:
50%
Explanation for A:
We're looking for how many numbers are odd, so theres 1, 3, 5 ,7, four numbers.
We have a total of 8 numbers.
To make any number a percent we move the point over to the right by two, which makes our final answer 50%
Answer to B:
37.5%
Explanation for B:
If the number is less than four, that means we need to find if it will roll the first three numbers. We, once again, have eight total possibilities
0.375 can be turned into our final answer, 37.5%