Answer:
Therefore the required resulting equation is
6 x minus 15 y = negative 63.
Negative 15 x + 15 y = 90
Step-by-step explanation:
Given:
......................Equation ( 1 )
......................Equation ( 2 )
To Find:
Expression after multiplying to eliminate y term,
Solution:
So to eliminate 'y' term we need to multiply equation 1 by a constant 3 and equation 2 by a constant -5, such that equations becomes
.....( 1 )
.....( 2 )
so now by adding new equation one and two we can eliminate y term that means -15y and +15y will get cancel,
Therefore the required resulting equation is
6 x minus 15 y = negative 63.
Negative 15 x + 15 y = 90
If both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is 182
The number of books that Pamela can shelf at a time = 26
The number of books that Debbie can shelf at a time = 7
If both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is the least common multiple of 26 and 7
The Least common multiple of 26 and 7 = 182
Therefore, if both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is 182
Learn more on Least Common Multiple here: brainly.com/question/363238
The way to find the factores is by seeking the polonomial's roots, or zeros!
To find the roots, we set the polinomial equation to zero:
x^2+16y^2=0
Then we solve this equation:
x^2=-16y^2
This is only true, if x=y=0.
The average between 12.00 and 15.00 seconds
can be defined in a few different ways.
Way #1: (speed)
Average speed =
(1/2) (the speed at 12 seconds + the speed at 15 seconds) .
Way #2: (speed)
Average speed =
(1/3) (the distance covered between 12.00 and 15.00 seconds)
Way #3: (velocity)
Average velocity =
(1/3) (distance between location at 12 sec and location at 15 sec)
in the direction from location at 12 sec to location at 15 sec.
That's the best we can do with the combination of given and
not given information in the question.
