First, write an equation system based on the problem
An equation for "the perimeter of a rectangle is 70 in" can be written as following
∴ 2l + 2w = 70 <em>(first equation)</em>
An equation for "the length is 11 in more than its width" can be written as following
∴ l = w + 11 <em>(second equation)</em>
Second, solve the equation by substitution method o find the dimension of the rectangle.
Substitute/plug l as (w+11) into the first equation
2l + 2w = 70
2(w + 11) + 2w = 70
2w + 22 + 2w = 70
4w + 22 = 70
4w = 70 - 22
4w = 48
w = 48/4
w = 12
The width of the rectangle is 12 in
Substitute w with 12 to the second equation
l = w + 11
l = 12 + 11
l = 23
The length of the rectangle is 23 in
Third, find the area of the rectangle
a = l × w
a = 23 × 12
a = 276
The area of the rectangle is 276 in²
Answer: (7x^2+144)/x^2
Step-by-step explanation:
f(h(x))=
f(12/x)=
(12/x)^2+7=
12^2/x^2 + 7=
144/x^2 +7=
144/x^2 +7*x^2/x^2=
144/x^2+7x^2/x^2=(7x^2+144)/x^2
Answer:
(x+3), (x-3), and (x+4)
I’m not so sure about the question but I hope this helps
Answer:
Step-by-step explanation:
I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thank me..
