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2 years ago

Please solve the challenge problem J

Mathematics

1 answer:

Verdich [7]2 years ago

6 0

Answer: (7x^2+144)/x^2

Step-by-step explanation:

f(h(x))=

f(12/x)=

(12/x)^2+7=

12^2/x^2 + 7=

144/x^2 +7=

144/x^2 +7*x^2/x^2=

144/x^2+7x^2/x^2=(7x^2+144)/x^2

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Explain why 0.4×10=4<br><br> helpppppppppppppp meeee

Anton [14]

4/10= 0.4

So if 0.4x10=4, That means that 4. Is 4/10 of 10.

6 0

4 years ago

Which expression is equivalent to sqrt8x^7y^8? assume x>0

Ilia_Sergeevich [38]

Answer:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

Step-by-step explanation:

Given

$\sqrt{8x^7y^8$

Required

Evaluate

$\sqrt{8x^7y^8$

Separate each factor with multiplication sign

$\sqrt{8*x^7*y^8$

Express 8 as 4 * 2 and $x^7$ as $x^6 * x$

$\sqrt{4 * 2 *x^6 * x*y^8$

Split each factor

$\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Evaluate $\sqrt4$

$2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Apply law of indices:

$2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}$

$2 * \sqrt{2} * x^3 * \sqrt{x} * y^4$

Reorder

$2* x^3 * y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2*x}$

$2x^3y^4 * \sqrt{2x}$

$2x^3y^4 \sqrt {2x$

Hence:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

8 0

3 years ago

Read 2 more answers

True or False:

Reil [10]

Answer:

True

Step-by-step explanation:

5 0

3 years ago

the slope of the line that passes through the points (-2,y) and (-5,7) is -2/3. what is the value of y?

Iteru [2.4K]

Answer:

Step-by-step explanation:

slope = rise/run = (7-y)/(-5-(-2)) = -2/3

3(7 -y) = -2(-3) . . . . . multiply by 3(-3)

7 -y = 2 . . . . . . . . . . . divide by 3

7 -2 = y = 5 . . . . . . . . add y-2

The value of y is 5.

7 0

3 years ago

Instructions

S_A_V [24]

The theoretical probability of getting two tails on two coin tosses is 0.25.

<h3>How to calculate the probability?</h3>

The theoretical probability is the ratio of the number of favorable outcomes to the number of possible outcomes. Given a coin is tossed twice.

We have to find the theoretical probability of tossing two tails. The probability of getting tails on the toss of a coin is 1/2 0r 0.5.

Therefore, the probability of getting two tails on two coin tosses is 0.5 × 0.5 or 0.25.

The theoretical probability that a coin toss results in two heads showing is 0.25.

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

7 0

2 years ago