Question

The population in thousands of people of a city is approximated by the function P(t) = 1200(2)0.1038twhere t is the number of years since 2011.
a. Find the population of this group in 2019.
b. Predict the population in 2029
a. The population of this group in 2019 is
(Round to the nearest thousand as needed.)
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Answer 1

The population of the group in 2019 is 2,134,000 people

Let P represent the population in thousands of people in the year t after 2011

Given the equation:

$P=1200(2)^{0.1038t}$

a) The population of the group in 2019, that is t = 8(2019 - 2011):

$P=1200(2)^{0.1038*8}=2134$

b) The population of the group in 2029, that is t = 18(2029 - 2011):

$P=1200(2)^{0.1038*18}=4382$

The population of the group in 2019 is 2,134,000 people

Find out more on equation at: brainly.com/question/2972832