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likoan [24]
3 years ago
15

Given: ABC is a right triangle with right angle C. AB = 14 centimeters and

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:7.6°

Step-by-step explanation:

Using sine formular

sinA/a =sinB/b

sin33/x = sin90/14

cross multiply

xsin90 = 14sin33

Divide bothside by sin90

x = 14sin33 / sin90

x= 7.6249 / 1

x = 7.6° to the nearest tenth.

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Answer:

Option B. -j = -h/-k is not correct

Step-by-step explanation:

As from the given scenario both the negative signs will be cancelled out giving positive j : -h/-k = -j

First option has: -j = -h/k In this case also the negative sign from both sides would be cancelled out.

Second option has: -h/-k = -j In this case negative signs cannot be cancelled out.

Third option has: h/-k = -j , negative sign would be cancelled from both sides.

Fourth option has: h/k = j , no negative sign on either side.

i hope it will help you!

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Step-by-step explanation:

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The height of a trapezoid is 6 in. and it’s area is 72 in to the 2nd power. One base of the trapezoid is 6 inches longer than th
Vitek1552 [10]

Given:

The height of the given trapezoid = 6 in

The area of the trapezoid = 72 in²

Also given, one base of the trapezoid is 6 inches longer than the other base

To find the lengths of the bases.

Formula

The area of the trapezoid is

A=\frac{1}{2} (b_{1} +b_{2} )h

where, h be the height of the trapezoid

b_{1} be the shorter base

b_{2} be the longer base

As per the given problem,

b_{2}=b_{1}  +6

Now,

Putting, A=72, b_{2}=b_{1}+6 and h=6 we get,

\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72

or, b_{1}+b_{1}+6 = \frac{(72)(2)}{6}

or, 2b_{1}+6 = 24

or, 2b_{1}=24-6

or, b_{1}= \frac{18}{2}

or, b_{1}=9

So,

The shorter base is 9 in and the other base is = (6+9) = 15 in

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One base is 9 inches for one of the bases and 15 inches for the other base.

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Answer to the problem:

D

Basically the -8 shows you the y value that the vertex has !! You can also use desmos to visualize

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