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igomit [66]
2 years ago
13

Simple true or false... d/dx{x^3e^x]=x^3e^x(3x+2) True or false

Mathematics
1 answer:
AlexFokin [52]2 years ago
3 0

Answer:

False.

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Factoring

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

\displaystyle \frac{d}{dx}[x^3e^x]

<u>Step 2: Differentiate</u>

  1. Derivative Rule [Product Rule]:                                                                     \displaystyle \frac{d}{dx}[x^3e^x] = \frac{d}{dx}[x^3]e^x + x^3 \frac{d}{dx}[e^x]
  2. Derivative Rule [Basic Power Rule]:                                                             \displaystyle \frac{d}{dx}[x^3e^x] = 3x^2e^x + x^3 \frac{d}{dx}[e^x]
  3. Exponential Differentiation:                                                                         \displaystyle \frac{d}{dx}[x^3e^x] = 3x^2e^x + x^3e^x
  4. Factor:                                                                                                           \displaystyle \frac{d}{dx}[x^3e^x] = (x^3 + 3x^2)e^x

∴ \displaystyle \frac{d}{dx}[x^3e^x] \neq x^3e^x(3x + 2)  but  \displaystyle \frac{d}{dx}[x^3e^x] = (x^3 + 3x^2)e^x.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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