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3 years ago

18

Mathematics

1 answer:

Lorico [155]3 years ago

8 0

Answer:

I just found it out, 200 Student tickets were sold.

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Find the zeros of polynomial x^2-3

Yakvenalex [24]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The required zeroes are ~

$\boxed{ \boxed {\sqrt{3}} \: \: and \: \: \boxed{- \sqrt{3} }}$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's equate the given polynomial with 0, to find its roots ~

that is ~

${x}^{2} - 3 = 0$

${x}^{2} - ( \sqrt{3} ) {}^{2} = 0$

$(x + \sqrt{3} )(x - \sqrt{3} ) = 0$

there are two cases,

Case # 1 - when (x + √3) = 0

$x + \sqrt{3} = 0$

$x = - \sqrt{3}$

and

Case # 2 - when (x - √3) = 0

$x - \sqrt{3} = 0$

$x = \sqrt{3}$

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Step-by-step explanation:

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Solve the following system of linear equations by elimination through addition.

Morgarella [4.7K]

Answer:

this is the method of elimination and how to do it

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3 years ago

Idk what it is asking.

Oksi-84 [34.3K]

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Jumbo burger with fried is 75%

chicken with salad is 65%

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36/42 = 24/r what is r

Alla [95]

Answer:

r=28

Step-by-step explanation:

36/42 = 24/r (determine the defined range)

36/42 = 24/r , r ≠ 0 ( Reduce the fraction)

6/7 = 24/r (cross multiply)

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