Answer:
Step-by-step explanation:
given,
initial price of buzz stock = $ 20 per share
after 20 days
stock price = $30 per share
after 40 days
the price = $35 per share
let say it is modeled by
y = ax² + b x + c
x = number of days
y = stock price
x = 0 y = 20
20 = a x 0 + b x 0 + c
c = 20
x = 20 y = 30
30 = 20² a + 20 b + 20
400 a + 20 b = 10...........(1)
x = 40 y = 35
35 = 40² a + 40 b + 20
1600 a + 40 b = 15...........(2)
solving equation (1)and (2)
a = - 1/160
b = 5/8
hence , the above equation is multipart function
Answer:
(a) 2 feet.
(b) 2 feet.
Step-by-step explanation:
We have been given that the velocity function 
in feet per second, is given for a particle moving along a straight line.
(a) We are asked to find the displacement over the interval 
.
Since velocity is derivative of position function , so to find the displacement (position shift) from the velocity function, we need to integrate the velocity function.
Using power rule, we will get:
![\left[\frac{t^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}}\right] ^4_1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bt%5E%7B-%5Cfrac%7B1%7D%7B2%7D%2B1%7D%7D%7B-%5Cfrac%7B1%7D%7B2%7D%2B1%7D%7D%5Cright%5D%20%5E4_1)
![\left[\frac{t^{\frac{1}{2}}}{\frac{1}{2}}}\right] ^4_1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bt%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%5Cright%5D%20%5E4_1)
![\left[2t^{\frac{1}{2}}\right] ^4_1](https://tex.z-dn.net/?f=%5Cleft%5B2t%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5Cright%5D%20%5E4_1)
Therefore, the total displacement on the interval would be 2 feet.
(b). For distance we need to integrate the absolute value of the velocity function.
Since square root is not defined for negative numbers, so our integral would be .
We already figured out that the value of is 2 feet, therefore, the total distance over the interval would be 2 feet.
Well...The sum of those radicals is 7 root 2 and that is a imperfect square root so this is irrational
Y= mx +b
4= 0(-2) +b
4= b
y= 0x +4
Have a great day!
Let me know if you have any questions
The measure of the angle FEG is probably the same as the measure of the angle FDG. There is nothing saying that EF is parallel to DG, but if so, the measure of the angle FEG is also 50º.
When the diagonals of a trapezium with two parallel bases inside of a circle are drawn, they make the same angle measure with those bases.
