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maks197457 [2]
3 years ago
12

A bag of mixed nuts has 14 almonds, 12 cashews, and 18 peanuts. If one nut is selected, what is the probability that a peanut is

chosen?
Provide the answer as a simplified fraction.
Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
7 0

18 / 44 = 9 / 22

There are 44 nuts in the bag, and 18 of them are peanuts. If you simplify the fraction, you get 9/22 chance of getting a peanut.

Dmitrij [34]3 years ago
6 0

Answer:

9 / 22

Step-by-step explanation:

combine 14, 12, and 18

=44

then, divide 18 by 44

then you get 9 / 22

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<img src="https://tex.z-dn.net/?f=3%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%202%20%5Cfrac%7B1%7D%7B4%7D%20%20-%201%20%5Cfrac%7B1%7D%
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Step-by-step explanation:

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Use copy dot flip to solve.

= 3 5/7 / 2/1

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