A bag of mixed nuts has 14 almonds, 12 cashews, and 18 peanuts. If one nut is selected, what is the probability that a peanut is
chosen?
Provide the answer as a simplified fraction.
2 answers:
18 / 44 = 9 / 22
There are 44 nuts in the bag, and 18 of them are peanuts. If you simplify the fraction, you get 9/22 chance of getting a peanut.
Answer:
9 / 22
Step-by-step explanation:
combine 14, 12, and 18
=44
then, divide 18 by 44
then you get 9 / 22
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