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maks197457 [2]
2 years ago
12

A bag of mixed nuts has 14 almonds, 12 cashews, and 18 peanuts. If one nut is selected, what is the probability that a peanut is

chosen?
Provide the answer as a simplified fraction.
Mathematics
2 answers:
LUCKY_DIMON [66]2 years ago
7 0

18 / 44 = 9 / 22

There are 44 nuts in the bag, and 18 of them are peanuts. If you simplify the fraction, you get 9/22 chance of getting a peanut.

Dmitrij [34]2 years ago
6 0

Answer:

9 / 22

Step-by-step explanation:

combine 14, 12, and 18

=44

then, divide 18 by 44

then you get 9 / 22

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Read 2 more answers
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

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2 years ago
Tony has 7/8 of a candy bar. he wants to split the bar into servings that are 3/10 of the bar. how many servings can he make?
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So, Tony can make 2 servings.
3 0
3 years ago
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