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2 years ago

Solve for angle S ? Please help

Mathematics

2 answers:

ASHA 777 [7]2 years ago

6 0

<h2>Answer:</h2>

∠s is the exterior angle of the given triangle(Δ).

And we know that exterior angle is equal to the sum of the other two opposite interior angles.

∠s = 48° + 48°

∠s = 96°.

BARSIC [14]2 years ago

3 0

Answer:

s= 96

Step-by-step explanation:

s°= 48° +48° (ext. ∠ of triangle)

s°= 96°

s= 96

☆ Exterior angle of a triangle

- The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

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Lesechka [4]

Answer:

Hourly Rate = $12.22 per hour

Step-by-step explanation:

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3 years ago

Determine the measure of each indicated angle. Show all necessary steps!

Rasek [7]

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1 year ago

Please help fast! (see picture)

valentina_108 [34]

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2 years ago

Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 a

krok68 [10]

Answer:

Jessie scored higher than Reagan.

Step-by-step explanation:

We are given that Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 and standard deviation 100.

Jessie scored 30 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 17 and standard deviation 5.

For finding who performed better on the standardized exams, we have to calculate the z-scores for both people.

1. Finding z-score for Reagan;

Let X = distribution of SAT scores

SO, X ~ Normal( $\mu=1000, \sigma^{2}=100^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 1000

$\sigma$ = standard deviation = 100

Now, Reagan scored 1140 on the SAT, that is;

z-score = $\frac{1140-1000}{100}$ = 1.4

2. Finding z-score for Jessie;

Let X = distribution of ACT scores

SO, X ~ Normal( $\mu=17, \sigma^{2}=5^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 17

$\sigma$ = standard deviation = 5

Now, Jessie scored 30 on the ACT, that is;

z-score = $\frac{30-17}{5}$ = 2.6

This means that Jessie scored higher than Reagan because Jessie's standardized score was 2.6, which is 2.6 standard deviations above the mean and Reagan's standardized score was 1.4, which is 1.4 standard deviations above the mean.

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3 years ago

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