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irga5000 [103]
2 years ago
14

Simplify -2a(7a^5-5a+5)

Mathematics
1 answer:
olga_2 [115]2 years ago
3 0
Here here here here here here here

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I need help on this it’s about trig identities
Cerrena [4.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha

\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha  }{cos\alpha (1 + sin\alpha) }

\frac{1  + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha  }{cos\alpha + sin\alphacos\alpha  }

\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha  }

\frac{2(1 + sin\alpha) }{cos\alpha(1 + sin\alpha ) }

\frac{2}{cos\alpha }

2sec\alpha

2.-

   sec²x - tanxsecx

\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}

\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}

\frac{1 - sinx}{cos^{2}x }

\frac{1 - sinx}{1 - sin^{2}x }

\frac{1 - sinx}{(1 - sinx)(1 + sinx)}

\frac{1}{1 + sinx}

3 0
3 years ago
Buying a new car can create a financial challenge because car
Triss [41]
If you get behind on a payment in messes you up
8 0
2 years ago
Which of the following expressions is equivalent to the expression x - (-3) ?
ziro4ka [17]
D.
X+3
I attached a picture

6 0
2 years ago
Ten engineering schools in the United States were surveyed. The sample contained 250 electrical engineers, 80 being women; 175 c
steposvetlana [31]

Answer:

There is a significant difference between the two proportions.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for difference between population proportions is:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

Compute the sample proportions as follows:

\hat p_{1}=\frac{80}{250}=0.32\\\\\hat p_{2}=\frac{40}{175}=0.23

The critical value of <em>z</em> for 90% confidence interval is:

z_{0.10/2}=z_{0.05}=1.645

Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering as follows:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

     =(0.32-0.23)\pm 1.645\times\sqrt{\frac{0.32(1-0.32)}{250}+\frac{0.23(1-0.23)}{175}}\\\\=0.09\pm 0.0714\\\\=(0.0186, 0.1614)\\\\\approx (0.02, 0.16)

There will be no difference between the two proportions if the 90% confidence interval consists of 0.

But the 90% confidence interval does not consists of 0.

Thus, there is a significant difference between the two proportions.

4 0
3 years ago
Whats a function rule for -3,-7,-11,-15
nikklg [1K]

Answer:

Subtract 4

Step-by-step explanation:

-3 - 4 = -7

-7 - 4 = -11

-11 - 4 = -15

7 0
3 years ago
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