Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
Answer:
Sine
Step-by-step explanation:
sine = opposite/hypotenuse
sin59 = x/16
6 because 18 divided by 3 equals 6
Let log5 125 = x
Removing log you get 5^x = 125
Rewrite 125 as 5^3
Now 5^x = 5^3
x = 3
You can write any decimal as a precent by moving the decimal 2 places to the right so
0.51 = 51%
5.1% < 51%
5.1% < 0.51
or, any precent can be written as a decimal by moving the decimal points two point to the left so
5.1% = 0.051
0.051 < 0.51
5.1% < 0.51
