Answer:
B
Step-by-step explanation:
a,b and c are the sides of a triangle if it satisfies:
a<b+c , b<a+c and c<b+a
Here, a=4 and b=7
We have to find c
i.e. all those c which satisfies:
4<7+c , 7<4+c and c<4+7=11
A.3 it is not true since it doesn't satisfies second inequality
B.5 it is true
C.7 it is true
D.9 it is true
E.11 This is clearly false, since it doesn't satisfies inequality third
F.17 This is clearly false, since it doesn't satisfies inequality third
Hence, correct options are:
B.5
C.7
D.9
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B=-14
reason:
1/7(-1)*-14
1/7*14
=2
These seem tough, but they are not that bad.
(f o g)(x)
That means to take function g when x = x (It just means that you don't need to do anything with the function) and substitute it into function f wherever there is a x value. (So basically g becomes what x equals)
Here is a visual representation of it.
(f o g)(x) = 2(9x + (3/2)) - (3/9)
We need to distribute the 2 to everything inside the parenthesis.
(f o g)(x) = 18x + (6/2) - (3/9)
Let's simplify the fraction on the right and left, then find a common denominator so we can add / subtract the two fractions.
(f o g)(x) = 18x + (3) - (1/3)
(f o g)(x) = 18x + (9/3) - (1/3)
Combine like terms.
(f o g)(x) = 18x + (8/3)
Our final answer is:
(f o g)(x) = 18x + 8/3
