Question

Solve this system of equations using substitution, show your work (ANSWER QUICK PLEASE)

Answer 1

Answer:

$\boxed{\sf{y=-50 \quad x=3}}$

Step-by-step explanation:

Isolate the term of x and y from one side of the equation.

y=-15x-5 and 11x+y=-17

First, you have to substitute.

$\sf{y=-15x-5=11x-15x-5=-17}$

Then, you solve.

$\sf{-4x-5=-17}$

Add by 5 from both sides.

-4x-5+5=-17+5

Solve.

-17+5=-12

-4x=-12

Divide by -4 from both sides.

-4x/-4=-12/-4

Solve.

-12/-4=3

x=3

y=-15*3-5

Solve.

PEMDAS stands for:

• Parenthesis
• Exponents
• Multiply
• Divide
• Add
• Subtract

15*3=45

Rewrite the problem down.

y=-45-5

Solve.

y=-50

Therefore, the correct answer is y=-50 and x=3.

I hope this helps you! Let me know if my answer is wrong or not.