We need cells for every day function. This includes significant processes like growth and development or protection from disease
Answer:
A. VG = 80
B. Broad sense heritability = 0.80
C. Narrow sense heritability = 0.30
D. Average yield = 430 Units
Explanation:
A. Given that
VA = 30
VD = 50
VI = assumed not available
Therefore
Total genetic variance (VG) = VA + VD
= 30 + 50
= 80
VG = 80
B. Given that
VP = 100
VG = 80
Broad sense heritability, H2 = VG/VP
= 80/100
= 0.80
C. Given that
VA = 30
VP = 100
Narrow sense heritability, h2 = VA/VP
=30/100
= 0.30
D. The difference in selection = 500 - 400
= 100
Recall,
Selection response is heritability multiplied by selection differential.
That is
R = h2S
Selection differential = 100
Heritability h2 = 0.30
Selection response = 0.30 × 100
= 30units
Therefore, expected average yield = 400 + 30
= 430 Units
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Answer:
The statement 2 best describes the next process taking place within the cell.
Explanation:
A kind of cell division, which is characterized by the differentiation of a single parent cell into two daughter cells that comprise equivalent chromosomes number is termed as mitosis or reductional division. In the given case, the arrangement of chromosomes at the equatorial plate indicates that the cell is currently in the metaphase stage of mitosis.
After going through the stage of metaphase, the cell moves into the anaphase stage. In the anaphase stage, the sister chromatids begin to segregate and move towards the opposite pole of the cell. Thus, statement 2 correctly illustrates the next stage of the cell.
Answer:
The following punnet square would be constructed from the above mentioned cross:
b b
B Bb Bb
B Bb Bb
A punnet square can be described as a diagram which is made to illustrate the outcomes of a cross.
The results from the above punnet square show that the offsprings produced from a cross between homozygous blue and brown parent, will all have blue feathers but they all will be heterozygous for the trait.